IB Specific Heat Capacity Lab

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Candidate Name: Sahaj Miyani

Candidate no.: 001424-049

Session: May 2009

IT used:

Graphical Analysis 3.1

Lab Partner: Radhey Choksi

Date:

Class : XI B5y

Contents

 

DESIGN (D)

INTRODUCTION:

This lab report will find the specific heat capacity of a metallic bob.

RESEARCH QUESTION:

How many joules of heat are required for the temperature to rise by 1 K of metallic bob of 1 Kg.?

BACKGROUD INFORMATION:

A solid of known mass is heated to a known temperature and placed in a calorimeter containing water at room temperature.  When all the three things reach the same temperature it is said to be at the state of equilibrium. Using the law of conservation of energy (heat gained = heat lost) we can find the specific heat capacity of the solid (Bob).

  • Specific heat capacity of water = 4182 Jkg-1K-1
  • Specific heat capacity of calorimeter = 385 Jkg-1K-1.

HYPOTHESIS:

Increase in the temperature of Water Bath will result in the increase of the total heat gained by water and calorimeter and vice versa.

Heat gained by Water and Calorimeter  Initial temperature of Solid (Bob)  Temperature of Water Bath

Assuming that the Equation of Thermal Equilibrium holds true and that no heat is lost to the environment the specific heat capacity of the solid can be calculated by:

  • MB × CB (T3 – T2) = (Mw × Cw (T2 – T1)) + (MC × CC (T2 – T1))
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Specific heat capacity of bob = (Heat gained by water + Heat gained by calorimeter) ÷ (Mass of bob × Temperature change of bob).

VARIABLE:

  • Independent (manipulated) variables
  1. Initial temperature of solid
  2. Mass of metal bob and calorimeter
  • Dependent (responding) variables
  1. Final temperature of metal bob, calorimeter and water
  2. Mass of water
  • Controlled variables
  1. Initial temperature of water (22°C) and calorimeter (41.35°C)
  2. Room temperature (air-condition was kept at a fixed temperature)
  • Unknown variable

Specific heat capacity of the solid (metal bob)

HOW TO CONTROL VARIABLES:

  • The same ...

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