• Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

Physics lab on propagation of errors. In this experiment I investigated the propagation of errors while calculating the volume of two objects.

Extracts from this document...

Introduction

PHYSICS LAB 5

PROPAGATION OF ERRORS

                                                     , By Satish Ahuja

In this experiment I investigated the propagation of errors while calculating the volume of two objects. I came to the conclusion that a measuring instrument like a screw gauge has some problematic limitations. This, along with other human factors, introduces uncertainties and errors in the measurement. Careful procedure can minimize these errors but cannot remove them completely. The errors in individual measurements contribute to the result of calculations using the measured quantities. Various precautions need to be taken to minimize errors in measurements and study of how these errors propagate during the various calculations needs to be taken.

The aim of this experiment was to investigate the propagation of errors while calculating the volume of a Cylindrical and a Spherical object.

My experiment included calculating the volume of two objects by two different methods.

 Apparatus: Vernier calipers, given spherical object, given cylindrical object, a measuring cylinder, and string.

...read more.

Middle

2 = 11 cm3

200 cm3

211 cm3

3. V3 = 12 cm3

200 cm3

212 cm3

4. V4 = 10 cm3

200 cm3

210 cm3

Therefore, the final volume is (12+11+12+10)/ 4

 = 11.25 cm3.

The error in this case is + 2 cm3.

So volume for the first case is 11.25cm3 + 2 cm3

DIAMETER OF SPHERE

MAIN SCALE READING

VERNIER SCALE

READING

1. D1 = 2.46 cm

2.4 cm

0.06 cm

2. D2 = 2.46 cm

2.4 cm

0.06 cm

3. D3 = 2.48 cm

2.4 cm

0.08 cm

4. D4 = 2.48 cm

2.4 cm

0.08 cm

5. D5 = 2.46 cm

2.4 cm

0.06 cm

TRUE VALUE = 2.46 cm

Now with the diameter we can calculate the volume of the sphere using the formula for volume of a sphere:

V=4/3 π r3

V = 4/3 x πx (2.46/2)3

Volume = 12.9cm3

The error is equal to thrice the percentage error of the radius as it is cubed.

...read more.

Conclusion

3 = 310 cm3

100 cm

410 cm

4. V4 = 309 cm3

100 cm

409 cm

Thus, the final volume (average) is (311+310+310+309)/ 4 = 310 cm3.

The error is = + 5 cm.

Hence the Volume = 310cm3 +5cm.

For volume of the cylinder

We calculate the volume by the formula V = πr2h

Thus, Volume = πx (9.5/2)2 x 6.4

                        = 305.614 cm3

The error is twice the percent error of the radius. (Since the radius is squared)

Error = 2 (% error of radius)

Error = 2 x (0.01/6.4) x 100

          = 0.03125 % of the volume

Thus, error = (0.03125/100) x 305.614

                   = 0.0955 cm3

Volume of Cylinder = 305.60 +0.096 cm3

I noticed that there is a big difference between both the methods (with the sphere and the cylinder). E.g.: - volume of sphere with water displacement is 10 +1 cm2, but when we use the formula it comes out to be 9.525 + 0.108 cm2. This shows us that with the correct precautions and methods, we can get an answer that has the least possible error and is therefore the most accurate. My expectation regarding the difference was hence right. I found this to be an engaging and eye-opening experiment and I enjoyed doing it. I look forward to more experiments of this type in the future

...read more.

This student written piece of work is one of many that can be found in our International Baccalaureate Physics section.

Found what you're looking for?

  • Start learning 29% faster today
  • 150,000+ documents available
  • Just £6.99 a month

Not the one? Search for your essay title...
  • Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

See related essaysSee related essays

Related International Baccalaureate Physics essays

  1. THermal Physics Lab

    Heat loss (J) of water Heat loss (J) of milk 180 -58604 + 975 -58435 + 969 360 -50232 + 840 -50895 + 848 540 -41860 + 704 -41470 + 696 720 -33488 + 567 -35815 + 603 900 -27209 + 462 -30160 + 510 1080 -25116 + 427 -26390

  2. Suspension Bridges. this extended essay is an investigation to study the variation in tension ...

    Firstly, I had planned to use a string of length equal to the distance between the two nails (i.e 138 cm). However, data collection became difficult for a relatively non-elastic string as the force applied could not produce an appreciable change in the vertical distance of the string.

  1. Aim of the Laboratory Experiment: Understanding of propagation of light waves phenomena by using ...

    and the light intensity of one of the sources I1 can be used to find the intensity of the second source I2. Variables Considering the fact that we have 3 tasks, the quantities that we measure change their nature. For the 1st and for the 2nd task: Independent variable -

  2. Aim: ...

    Also it was very important to keep the two metal spheres constant throughout the 3 trials, and more importantly not to get them mixed with one another since the incident ball had a greater mass than the target ball. Also kept constant was the initial height of the spheres and the place where we released the incident ball from.

  1. HL Physics Revision Notes

    Examples of forces which provide centripetal forces are gravitational forces (planets orbiting in a circle), frictional forces (car driving in circles), magnetic forces or tension (string). F=ma. a = v^2/r. Therefore, F=mv^2/r Topic 3 Thermal Physics: Temperature is a scalar quantity that gives indication of the degree of hotness or coldness of a body.

  2. In this experiment, a mechanism is prepared to observe the refraction of light and ...

    That means the angle between x-axis is 90°. There is no refraction just because of the light is perpendicular to x-axis. During the percentage error calculations literary value of refractive index of water is taken 1.334 (i.e 4/3). [6] So the percentage error is calculated with the formula of and it is found 0.2 % which is really low error.

  1. Experiment to compare the radiation of heat from different objects.

    in an error in the reading as the outer surface of the can is affected by external temperatures. Quantitative Data Table show the reading taken from the shining aluminum can at equal intervals of time Time (s)

  2. Rolling objects down a ramp Physics LAB

    (102 cm/s) ) Therefore velocity is 0.102 m/s and acceleration is 0.055 611.7 g= 6N (weight) Therefore force of static friction is approximately 22.5 N and the force of friction is approximately 21 N Wooden Block with Sandpaper base It took approximately 1.67 seconds to travel 75 inches. (114 cm/s)

  • Over 160,000 pieces
    of student written work
  • Annotated by
    experienced teachers
  • Ideas and feedback to
    improve your own work