• Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

Physics lab on propagation of errors. In this experiment I investigated the propagation of errors while calculating the volume of two objects.

Extracts from this document...

Introduction

PHYSICS LAB 5

PROPAGATION OF ERRORS

                                                     , By Satish Ahuja

In this experiment I investigated the propagation of errors while calculating the volume of two objects. I came to the conclusion that a measuring instrument like a screw gauge has some problematic limitations. This, along with other human factors, introduces uncertainties and errors in the measurement. Careful procedure can minimize these errors but cannot remove them completely. The errors in individual measurements contribute to the result of calculations using the measured quantities. Various precautions need to be taken to minimize errors in measurements and study of how these errors propagate during the various calculations needs to be taken.

The aim of this experiment was to investigate the propagation of errors while calculating the volume of a Cylindrical and a Spherical object.

My experiment included calculating the volume of two objects by two different methods.

 Apparatus: Vernier calipers, given spherical object, given cylindrical object, a measuring cylinder, and string.

...read more.

Middle

2 = 11 cm3

200 cm3

211 cm3

3. V3 = 12 cm3

200 cm3

212 cm3

4. V4 = 10 cm3

200 cm3

210 cm3

Therefore, the final volume is (12+11+12+10)/ 4

 = 11.25 cm3.

The error in this case is + 2 cm3.

So volume for the first case is 11.25cm3 + 2 cm3

DIAMETER OF SPHERE

MAIN SCALE READING

VERNIER SCALE

READING

1. D1 = 2.46 cm

2.4 cm

0.06 cm

2. D2 = 2.46 cm

2.4 cm

0.06 cm

3. D3 = 2.48 cm

2.4 cm

0.08 cm

4. D4 = 2.48 cm

2.4 cm

0.08 cm

5. D5 = 2.46 cm

2.4 cm

0.06 cm

TRUE VALUE = 2.46 cm

Now with the diameter we can calculate the volume of the sphere using the formula for volume of a sphere:

V=4/3 π r3

V = 4/3 x πx (2.46/2)3

Volume = 12.9cm3

The error is equal to thrice the percentage error of the radius as it is cubed.

...read more.

Conclusion

3 = 310 cm3

100 cm

410 cm

4. V4 = 309 cm3

100 cm

409 cm

Thus, the final volume (average) is (311+310+310+309)/ 4 = 310 cm3.

The error is = + 5 cm.

Hence the Volume = 310cm3 +5cm.

For volume of the cylinder

We calculate the volume by the formula V = πr2h

Thus, Volume = πx (9.5/2)2 x 6.4

                        = 305.614 cm3

The error is twice the percent error of the radius. (Since the radius is squared)

Error = 2 (% error of radius)

Error = 2 x (0.01/6.4) x 100

          = 0.03125 % of the volume

Thus, error = (0.03125/100) x 305.614

                   = 0.0955 cm3

Volume of Cylinder = 305.60 +0.096 cm3

I noticed that there is a big difference between both the methods (with the sphere and the cylinder). E.g.: - volume of sphere with water displacement is 10 +1 cm2, but when we use the formula it comes out to be 9.525 + 0.108 cm2. This shows us that with the correct precautions and methods, we can get an answer that has the least possible error and is therefore the most accurate. My expectation regarding the difference was hence right. I found this to be an engaging and eye-opening experiment and I enjoyed doing it. I look forward to more experiments of this type in the future

...read more.

This student written piece of work is one of many that can be found in our International Baccalaureate Physics section.

Found what you're looking for?

  • Start learning 29% faster today
  • 150,000+ documents available
  • Just £6.99 a month

Not the one? Search for your essay title...
  • Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

See related essaysSee related essays

Related International Baccalaureate Physics essays

  1. THermal Physics Lab

    3 720 21 24 5 900 19 22 6 1080 19 21 7 1260 18 21 9 1440 17 19 10 1620 15 18 12 1800 15 18 14 Calculating heat loss for water: Density of water = 1 Kg/L (in the calculations below the density of water is rounded to 1 Kg/L.

  2. Suspension Bridges. this extended essay is an investigation to study the variation in tension ...

    The force applied in the form of a spherical bob was movable and thus, the readings were taken starting close to the first rigid support and moving away such that by the time I reached the second rigid support, they were 10 points at which the vertical distance was measured.

  1. IB Physics Lab - Resistance

    be slightly less than the theoretical total resistance of that circuit, most likely due to the tolerance of the resistor(s). There was only one group of data that didn't follow this trend: Trial 1 of Parallel Circuits, where there was a positive 0.14% error.

  2. Pendulum Lab

    given varied in the number of figures given (tenths of a second for the first stopwatch and hundredths of a second for the second stopwatch), however due to the general inaccuracy of the testers reaction time the uncertainty will be set at (�0.1s)

  1. Aim: ...

    Ball covered by itself: 46.2 cm To find initial momentum, We must have the velocity, and in order to have that we must have the time. S = 1/2 at� , isolate the t, we then have t = V2s / g where g = gravity = 9.8 m/s� Therefore we have, t = V 2(0.824)

  2. HL Physics Revision Notes

    Newton?s third law states that when a force acts on a body, an equal and opposite force acts on another body somewhere in the universe. One example would be two roller-skater?s pushing off one-another Additional: Mass is the amount of matter contained in an object measured in kg, whilst weight is a force measured in N.

  1. Rocket Physics Lab

    Minimum value is calculated by taking the average value and subtracting by the minimum value. Maximum Minimum Full sized paper rocket (m) ± 0.005m 0.458 0.412 ¾ size paper rocket (m) ± 0.005m 0.206 0.234 2/3 size paper rocket (m)

  2. In this experiment, a mechanism is prepared to observe the refraction of light and ...

    That means the angle between x-axis is 90°. There is no refraction just because of the light is perpendicular to x-axis. During the percentage error calculations literary value of refractive index of water is taken 1.334 (i.e 4/3). [6] So the percentage error is calculated with the formula of and it is found 0.2 % which is really low error.

  • Over 160,000 pieces
    of student written work
  • Annotated by
    experienced teachers
  • Ideas and feedback to
    improve your own work