• Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

Precision Lab. Question: What is the density of 2 unknown liquids, and how precise are the measurements used to make the calculations?

Extracts from this document...


IB # 000345-153

Measuring Precision in Liquid Measurements

IB Physics SL Lab


IB Physics SL

Question: What is the density of 2 unknown liquids, and how precise are the measurements used to make the calculations?


Background Information: The density of a liquid, ρ, is calculated by dividing mass by volume, m/v. This quantity, thus, is a measurement of the mass of an object per cubic unit. Precision can be defined as the accuracy of a measurement when compared to other measurements, not necessarily accurate when compared to the theoretical measurement.  In other words, all measurements made are within error range of each other, and are thus qualified as being precise.


  • 2 unknown liquids: one blue and one green.
  • A liquid of known density: ethyl alcohol.
  • A 100 mL graduated cylinder
  • A balance
  • 2 250 mL beakers
...read more.





















        Liquid A: 52.62/ 50  =  1.0524

        Liquid B: 52.53/49.9 =  1.0527

        Isopropol alcohol = 45.07/50 = .9014


        Slope of Liquid A: 1.062 Equation: Y = 1.062*X

        Slope of Liquid B: 1.0426 Equation: Y = 1.0426*X

        Slope of Isopropol Alcohol: .877 Equation: Y= .877*X

...read more.


        The water measurements can be used as an indicator of accuracy and precision because water’s density is 1 mg/ mL, and thus you can determine how close your measurements are to the known value. They can also be used to determine precision, as each water subset should have the same density, so if the densities you measure are close to each other, then you are fairly precise. Based on their measurements, my groups was fairly precise in our measurement.

...read more.

This student written piece of work is one of many that can be found in our International Baccalaureate Physics section.

Found what you're looking for?

  • Start learning 29% faster today
  • 150,000+ documents available
  • Just £6.99 a month

Not the one? Search for your essay title...
  • Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

See related essaysSee related essays

Related International Baccalaureate Physics essays

  1. Physics Extended essay

    he sees objects at rest such as on top of a table or fixed to a wall, he concludes that because the object is at rest, hence there is no force acting on it. However, that is a misconception that there is no force acting on the object.

  2. IB Specific Heat Capacity Lab

    � 1156.25 = 11.14 % � 1156.25 = � 128.81 J Heat absorbed by Calorimeter (HC) Mc � Cc � ?T = 41.35 � 0.385 � 4.50 = 71.64 J = [((0.01 � 41.35) � 100) + 11.11 %] � 71.64 = 11.13 % � 71.64 = � 7.98 J Heat lost by Bob (HB)

  1. In this extended essay, I will be investigating projectile motion via studying the movement ...

    is converted into the linear kinetic energy of the metal ball upon release. Hence, the projection velocity of metal ball in the experiment is less than we predicted, resulting in a smaller horizontal range. * After the metal ball is launched, it is not only subject to the influence of gravity, but also to the air resistance.

  2. Energy density experiment - Aim: To determine the energy density of ethanol

    Calculating mass of water and uncertainties 2. Calculating temperature of water and uncertainties 3. Calculating thermal energy 4. Calculating average thermal energy 5. Calculating uncertainty of the average thermal energy using maximum deviation Sample Calculation 1. Calculating mass of water and uncertainties: E.g.

  1. Thermal Properties of Liquids

    Furthermore, any result or raw data will be rounded up to two decimal places in order to ensure accuracy. This will leave no room for human error regarding any calculations throughout this investigation. In order to ensure the creditability and the accuracy of my results, each substance/liquid chosen for this

  2. DCP+CE Energy Density of Ethanol

    The uncertainty of gained data is �0.7MJ/kg. As the theoretical value is 26.8MJ/kg, it does not lie in between the uncertainty range. This is because of random error carried out throughout the whole experiment. As there are heat loss during the process of heating the water, there are a lot

  1. Energy Density of Ethanol

    To calculate the percentage difference between the data gained and the theoretical value; Percentage Difference = (theoretical value - data gained)/(theoretical value) x 100 = (26.8MJ/kg - 9.3MJ/kg)/(26.8MJ/kg) x 100 = (17.5MJ/kg)/(26.8MJ/kg) x 100 = 0.65298 x 100 = 65.298% = 65% There is 65% difference between the data gained and theoretical data.

  2. Physics lab - density

    Dividing 251.7 by 30, we get 8.39. Thus, = (8.39 � 0.1) g cm-3 = (8.4 � 0.1) g cm-3 Below are the results for the readings for the aluminum materials: Table 2 Material Mass m/g ?m = � 0.1 g Volume v/cm3 ?v = � 3 cm3 Density ?/g cm-3 ??

  • Over 160,000 pieces
    of student written work
  • Annotated by
    experienced teachers
  • Ideas and feedback to
    improve your own work