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Uncertainty in Atwoods machine lab. Measuring acceleration.

Extracts from this document...

Introduction

Alejandro Serruto Servat

Physics Report

Uncertainty in Atwood’s machine

Alejandro Serruto Servat

image00.pngimage01.png


Lab Report: Physics

Question

How does acceleration of the system vary according to the difference in between masses?

Procedure

  1. Set up a pulley system using a wheel
  2. Place four 50g blocks in each side of the rope that rests in the pulley.
  3. Pull one of the weights down and release it without pushing it or pulling it and record the acceleration using the sensor and logger pro.
  4. Measure the acceleration by measuring the slope of the graphic.
  5. Record your data
  6. Repeat each step but taking 50 grams off from one of the sides of the pulley and placing it in the other side, unbalancing the weight.

Variables

  • Independent: The mass in each side of the pulley (g)
  • Dependent: The acceleration of the motion (ms-2). The difference of mass on each side of the pulley
  • Control: The total mass in the system.
...read more.

Middle

-2)

250g

150g

400g

100g

2.39

2.20

2.38

2.32

300g

100g

400g

200g

4.78

4.80

4.84

4.8

350g

50g

400g

300g

6.92

7.04

6.86

6.94

Table Analysis

When the mass of the system was unbalanced, I figured out that the more unbalanced the mass on both sides of the pulley then the motion will have a greater acceleration. This is due to the larger weight force that the side of the system with more mass has; this produces a bigger force in the direction of the side with a larger weight force.

This can be explained with the Acceleration formula in Dynamic Systems: (Wb-Wa)/(Ma+Mb)
Graphicimage02.png

...read more.

Conclusion

Wa=Ma x g → Wa= 150 x 9.81 →Wa=1471.5 newtons

Wb=Mb x g→ Wb= 250 x 9.81 →Wb=2452.5 newtons

A= (Wb-Wa)/(Ma+Mb) → 2452.5 – 1471.5/250 + 150 = 2.45 ms-2

The result is almost the one that I got as the final average. This shows that the weight force and the mass are directly proportional and so affecting proportionally the acceleration of the system.

Now that we got that result, what would happen if taken in consideration? The measuring limit would be in this case 0.5 grams. If this was applied then the accelerations would be

Weight difference

Acceleration with Original Weight

Acceleration with +0.5 grams of weight

Acceleration with -0.5 grams of weight

100

2.45ms^-2

2.44ms^-2

2.45ms^-2

200

4.9 ms^-2

4.89ms^-2

4.89ms^-2

300

7.35 ms^-2

7.32ms^-2

7.37ms^-2

...read more.

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