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Effect Of An Inhibitor Such As Copper Sulphate On The Activity Of Catalase

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Introduction

Effect Of An Inhibitor Such As Copper Sulphate On The Activity Of Catalase The enzyme Catalase catalysis the decomposition of Hydrogen Peroxide to form smaller molecules: water and oxygen gas. In the reaction: 2H2O2 ------------> 2H2O + O2 The aim of this investigation is to find out how different concentration of Copper Sulphate (inhibitor) effect the activity of the enzyme Catalase. Hypothesis: As the concentration of Copper Sulphate increases the activity of Catalase will decrease and vice versa. In other word, at one extreme (high concentration) of CuSO4, the production of Oxygen will likely to stop completely and at the other extreme (low concentration) of CuSO4 the production of Oxygen is likely to continue with out no change. If the amount of inhibitor is fixed, then increasing the substrate concentration can reduce chances of inhibition by CuSO4. As two types of molecules are competing for the Catalase active site. The more H2O2 molecules there are, the less likely is it that CuSO4 (inhibitor) ...read more.

Middle

Research that I carried out on the internet, I found out that the Fe ion is found in the active site of yeast (Catalase). This means that Cu ions can displace the Fe ions (in enzyme) thus inhibit Catalase, and consequently disruption can be caused to the configuration of hydrogen bonds and the hydrophobic interaction which is holding the enzyme molecule. Method Part A: Apparatus * A conical flask to place the mixture of the enzyme, substrate and the inhibitor * A 5ml syringe to inject 2ml of yeast (catalase) enzyme into the mixture * A gas syringe to collect and measure the volume of Oxygen gas is produced within specific time interval * A clamp to hold the gas syringe * 13 test tubes 6 for different concentration of inhibitor and 6 for the substrate and 1 for water * 3 100ml measuring cylinders to measure out the volume of each variables * A stop clock to measure rate of production of Oxygen gas * A test tubes rack will be needed to hold the ...read more.

Conclusion

And see how much oxygen gas is collect within every five seconds of the reaction time * I will carry out each reaction for 60 seconds * Record the amount gas produced in my results table by reading of the gas syringe * I will repeat each experiment twice. This will be done to give an average volume of gas produce within the given time MY RESULT TABLE TUBES/TIME 10 20 30 40 50 60 A1 19 35 44 48 54 57 A2 21 35 46 49 54 58 AVE O2 CM3 20 35 45 48.5 54 57.5 B1 18 30 36 42 48 53 B2 19 32 36 42 48 55 AVE O2 CM3 18.5 31 36 42 48 54 C1 18 28 31 35 38 43 C2 19 26 32 35 38 41 AVE O2 CM3 18.5 27 31.5 35 38 42 D1 13 21 26 31 34 38 D2 12 22 27 31 33 38 AVE O2 CM3 12.5 21.5 26.5 31 33.5 38 E1 7 12 14 16 17 18 E2 7 12 14 16 17 19 AVE O2 CM3 7 12 14 16 17 18.5 Dublur Hussain Enzyme Coursework ...read more.

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