• Join over 1.2 million students every month
• Accelerate your learning by 29%
• Unlimited access from just £6.99 per month
Page
1. 1
1
2. 2
2
3. 3
3
4. 4
4
5. 5
5

The Energy Levels of Molecules

Extracts from this document...

Introduction

The Energy Levels of Molecules The phenomena of chemistry cannot be understood thoroughly without a firm grasp of the principle concept of quantum mechanics. When talking about energy levels, quantisation has to be considered, and this quantisation is the basic assumption of Quantum theory. This is when all the energy levels are quantised meaning that they can have only discrete values. This quantisation is defined through a quantum number, which usually have integers or half integers as values. These quantum numbers can only be fixed values whereas a classical particle can have any value when changing from one energy level to another. The molecule normally accepts one quantum of energy and the size of this quantum must be exactly the same as the difference between these two levels. Therefore this statement describes us the quantisation of energy. An element can only be present in certain energy levels corresponding to various quantum states (as shown below), but the energy of an electron cannot be found between any shown levels. Energy quantisation is universal because it holds for all kinds of systems like atoms, nuclei, molecules or electrons in solids. The principle energy levels of electrons Shell Principle Quantum Number Period (horizontal row) Maximum Number of Electrons = 2n2 Energy sublevels K 1 1 2 S L 2 2 8 S p M 3 3 - 4 18 S p d N 4 4 - 6 32 S p d f O 5 5 - 7 32 (2n2 = 50) ...read more.

Middle

From this equation the only unknown is I (moment of inertia / kg m2), but this can also be calculated by the following: I = m1m2 ? (r)2 Where m = mass (kg) m1 +m2 r = bond length (m) Now the Rotational energy can be calculated. Note that in this case the lowest energy state corresponds to the lowest rotational quantum number, which in this case is zero so therefore the molecule can have zero rotational energy. Vibrational Energy The Vibrational energy can also be calculated from the following equation: EV = (V + 1/2)h wosc Where V = Vibrational quantum number (0, 1, 2, 3, 4 etc. and not In between values, and no values less than 0) wosc = Oscillation frequency of molecule Where wosc = 2 ?? Where ? = frequency (Hz) ? = 1 k Where k = constant 2? � � = reduced mass = m1m2 m1 + m2 wosc could also be calculated by the following providing that the values are known: wosc = k Where k = constant � � = reduced mass (as shown previously) Therefore when a molecule moves from Level 0 to Level 1: For level 0 : EV=0 = 1/2 h wosc This value is commonly known as the vibrational zero point. But when the vibrational quantum number equals 1, the corresponding energy is: For Level 1 : EV=1 = 3/2 h wosc The change in energy would therefore be ...read more.

Conclusion

If we consider energy states 1 and 2 (i.e. E1 & E2)/ J molecule-1, the Boltzmanns equation shows that at a temperature the number of molecules in the two states, n1 and n2 would be given by the following: n2 = e - (E2 - E1) / kT Boltzmanns Equation n1 Where n = number of molecules E = the energy value of the energy level (J) K = Boltzmanns constant (1.3805 ? 10-23JK-1) T = Temperature (K) This equation shows the exponential dependency explicitly. It represents that the spread of the number of molecules to high energies, increasing with temperature. The energy kT is the dividing line between states that have significant number of molecules and those that have not. The Boltzmanns constant could be calculated as follows: K = R Where R = Gas constant (8.3145 JK-1mol-1) NA NA = Avagadros constant (6.0223 ? 1023) Just to add to this as we are talking about the Boltzmanns constant, the internal energy for one atom or a molecule where the rotational levels are widely spaced at a particular temperature (or a low temperature) can be calculated as follows: U = 3/2 KT Where U = Internal energy of the molecule (J) K = Boltzmanns constant (1.3805 ?10-23 JK-1) T = Temperature (k) We can say that the Bolzmanns constant can be defined as the amount of energy required to raise the temperature of an atom by one kelvin. Mudassar Azam Dr. H. Morris Rm 207 07/12/2003 ...read more.

The above preview is unformatted text

This student written piece of work is one of many that can be found in our University Degree Microbiology section.

Found what you're looking for?

• Start learning 29% faster today
• 150,000+ documents available
• Just £6.99 a month

Not the one? Search for your essay title...
• Join over 1.2 million students every month
• Accelerate your learning by 29%
• Unlimited access from just £6.99 per month

Related University Degree Microbiology essays

1. Identification of an Unknown Enterobacteriaceae. The purpose of the experimental determination of an unknown ...

(Alachi, P. 2007) Urease test was performed by spot inoculated the unknown on a urea agar plate and incubated overnight at 35 C. The purpose of this test was to check if the enzyme urease is produced to hydrolyzed urea to ammonia and carbon.

2. The biology of Fusarium oxysporum f. sp. gladioli, causal agent of corm rot of ...

After solidification the plates were inoculated with PDA discs (10 mm-diameters) taken from the edge of actively growing cultures with a sterile cork-borer. The plates were sealed with Prafilm(Japan, Co.). Five replicates were prepared for each. Growth media. To study the effect of different nutrients on F.oxysporum f.

1. Describe the Concept and Discuss the Importance of Homeostasis

The water temperature is initially adjusted to an equilibrium level, or set point. When the water temperature deviates below this set point, the sensor maintains the heater switch in the 'on' position. When the set point temperature is achieved, the heater switch turns 'off', and further heating ceases, until the temperature again drops below the set point.

2. &amp;quot;So many peptides, so few grooves&amp;quot; - compare the ways in which specific antigen ...

and � chains. These chains are organized into 3 complementary-determining regions (CDRs). Similarly, the variable regions of the heavy and light chains of antibodies each form 3 CDRs, which contact the Ag. However, unlike the MHC and the TCR, the peptide-binding site of Abs evidently makes contact with the tertiary structure of the whole epitope, not just with certain AA residues.

• Over 160,000 pieces
of student written work
• Annotated by
experienced teachers
• Ideas and feedback to
improve your own work