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Statistics report

Extracts from this document...

Introduction

Vietnam National University, Hanoi School of Business 144 Xuan Thuy, Cau Giay District, Hanoi, Vietnam, Tel. 84-4-7680456 Fax: 84-4-7680455 www.hsb.edu.vn Mark MANAGERIAL REPORT To: Board of Directors From: Nguyen Huu Hung (Mr.) ReMBA#7 Date: 4th March 2009 Dear Sir or Madam, This is my full report about Par, Inc., and Skaff Application Company. I used statistics analysis to express the result. Case 1: Par, Inc., Par, Inc. has produced a new type of golf ball. The company wants to know if this new type of golf ball is comparable to the old ones. Therefore they did a test, which consists out of 40 trials with the current and 40 trials with the new golf balls. The testing was performed with a mechanical fitting machine so that any difference between two the mean distanced for the two models could be attributed to a difference in the two models. The purpose of this managerial report is to provide a deep statistics analysis so that Par, Inc.,'s Board of Directors can rely on. We use Hypothesis Testing to test the mean (of normal distribution) of the driving distances of the current and new golf balls. For the current balls: * Number of observations: * Population mean: * Sample mean: * Standard deviation: For the new balls: * Number of observations: * Population mean: * Sample mean: * Standard deviation: Null Hypothesis : �1 - �2 = 0 (the driving distances of the current balls and the new balls are equal) ...read more.

Middle

2. Mean of sales are different between of stores Sales (000) Mall Location Sales (000) Mall Location 5.17 0 6.00 1 5.78 0 6.00 1 4.84 0 8.50 1 6.12 0 8.80 1 6.40 0 9.96 1 7.10 0 10.12 1 7.50 0 11.87 1 9.30 0 9.83 0 10.70 0 10.45 0 11.32 0 11.91 0 Sales on Mall Location (0) Sales on Mall Location (1) Mean 8.186153846 8.75 Standard Error 0.689986565 0.82035707 Median 7.5 8.8 Mode #N/A 6 Standard Deviation 2.487781939 2.17046078 Sample Variance 6.189058974 4.7109 Kurtosis -1.639940557 -0.88293061 Skewness 0.132852082 -0.15734601 Range 7.07 5.87 Minimum 4.84 6 Maximum 11.91 11.87 Sum 106.42 61.25 Count 13 7 Advertising Expense (000) Mall Location Advertising Expense (000) Mall Location 59.00 0 61.00 1 62.50 0 61.00 1 61.00 0 57.20 1 12.50 0 24.10 1 35.80 0 27.70 1 59.90 0 57.20 1 35.80 0 62.70 1 27.90 0 24.00 0 44.30 0 49.20 0 23.00 0 55.80 0 3. Mean of Advertising Expense are different between of stores Advertising Expense on Mall Location (0) Advertising Expense on Mall Location (1) Mean 42.36153846 50.1285714 Standard Error 4.714591894 6.31505059 Median 44.3 57.2 Mode 35.8 61 Standard Deviation 16.99870282 16.7080534 Sample Variance 288.9558974 279.159048 Kurtosis -1.304928698 -0.78929379 Skewness -0.326194972 -1.18326114 Range 50 38.6 Minimum 12.5 24.1 Maximum 62.5 62.7 Sum 550.7 350.9 Count 13 7 4. CI for proportion of the stores having Adv. Expense larger or equal than USD 50,000 Adv.Expense (000) ...read more.

Conclusion

- Mall Location variable: Null Hypothesis : = 0 (the Mall Location is not significant) Alternative Hypothesis : 0 (the Mall Location is significant) From the above ANOVA table's P-value we can see that: P-value of Mall Location is 0.5621> 0.05 so we can not reject null hypothesis, it means that 0.5621 is significant. * Testing for overall significance of the model Hypothesis: Null Hypothesis : ==== 0 (no linear relationship) Alternative Hypothesis : at least one 0 (at least one independent variable affects Y) We can use F-Test or P-value to evaluate the significance of overall model In this case K=4 (numerator) and (n-K-1)=(n-5) (denominator) d.f. The decision rule is: Reject if F> From the above ANOVA table's value we can see that: < 10.24 --> reject . There is evidence that at least one independent variable affects Y. Or we can also use P-value (significance F) to evaluate the significance of overall model From the above ANOVA table's value we can see that: P-value (significance F) = 0.0004 <0.05 --> reject * Whether or not Mall Location affect on sales of the stores? From the above ANOVA table's P-value we can see that: T-value for Mall Location is 0.59389586 with P-value is 0.5621> 0.05 it means that 0.5621 is significant or Mall Location affects on sales of the stores. * What is the estimated value of sales of a store which is located in a mall, in a region with %unemployed 4%, population 18,000,000 and this store invests 40,000USD for Advertising? From the Multiple regression model: We replace data (numbers) then we have ?? ?? ?? ?? Assignment No.2 - Case No.1&2 Page 1 of 10 ...read more.

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1. Statistics report

Freq. American Express 2 2% 0.02 Discover 4 4% 0.04 Mastercard 14 14% 0.14 Proprietary Card 70 70% 0.70 Visa 10 10% 0.10 Total 100 100% 1.00 FREQUENCY DISTRIBUTION Net sales Range of Net sales Count Freq.(%) Rel. Freq.