Calorimetry: Enthalpy of Neutralization

Introduction

The purpose of this experiment is to calculate the heat of reactions using the calorimetry and to discover the molarity of the unknown HCl solution. There were three reactions to be observed: they are neutralization of NaOH with HCl, neutralization of NaOH with HNO3, and neutralization of NaOH with phenol.

Throughout this experiment, one will be using the Calorimetry technique to perform numerous neutralizations. A calorimeter is a device for measuring quantities of heat in chemical reactions. In this lab, the "coffee-cup" calorimeter was used which is a simpler calorimeter than the bomb calorimeter. The reactants are mixed in a Styrofoam cup where the reaction will occur, and a thermometer is used to measure the changes in temperature. Styrofoam is a good heat insulator because there is little transfer between the cup and surrounding air, creating a isolated system. However, the coffee cup calorimeter has a internal pressure that is equal to atmospheric pressure because it is not a sealed system. This causes the initial pressure of the reactants equal to the final pressure of the system after the reaction. Also, the heat of reaction, q, equals the enthalpy change of the system ΔH. The heat of reaction is the heat released or absorbed during a complete chemical reaction. A reaction is exothermic when it produces a temperature increase in an isolated system, and a endothermic reaction is when reaction causes a temperature decrease in an isolated system.

In this experiment, one will be measuring the enthalpy changes during a neutralization reaction. Two types of neutralizations were performed, one involving strong electrolytes and weak electrolytes. Strong electrolytes (strong acids and bases) completely dissociated into ions in diluted solutions, such as the HCl, NaOH, and NaCl. The heat of reaction for all strong electrolytes all produce the same amount of heat: q=-55.90 kJ of heat per mol of H+. At a constant pressure, the heat of the reaction equals the enthalpy change ΔH, therefore ΔH also equals -55.90 kJ. The neutralizations involving weak electrolytes (weak acids and bases) will partially dissociate into ions, such as NH3, CH3COOK, and phenol. This neutralization will be either be smaller or larger than -55.90 kJ of heat per mol of H+. Because it depends on the nature of the weak electrolyte which can be either endothermic or exothermic. The formula used to calculate the heat of reactions is ∆H = q = specific heat (s) * mass (m) * change in temperature (∆T).

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Materials and Procedure

Refer to the lab manual pg. 50-52. experiment #4 (Department of Chemistry, 2009). All materials and procedures were performed with no deviations.

Experimental Observations

Part A: Neutralization of NaOH with HCl

Concentration of NaOH = 2.335M,         Temperature of NaOH = 23.5°C

Concentration of HCl = 1.9027M,        Temperature of HCl = 23.5 °C

Table1: Temperature Change for Neutralization of NaOH and HCl (First Trial)

Figure 1: Temperature Change for Neutralization of NaOH and HCl (First Trial)

Table2: Temperature Change for Neutralization of ...

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