Carolina Andreoli

Math Portfolio

Fri, 1 October 2004

Growth Functions

a) Table 1:

b) Graph 1: Ordered Pairs (t, A)

t

        

  1. A0 = 100

b = 2

c =

A = A0b ct

A = 100(2)1/3t

  1. = A0b ct = A0ekt

= b ct = ekt

= ctlogb = ktloge

= clogb = kloge

k =

k =

k =

k = 0.231

A = 100(e0.231t)

                       t        

t = 5

A = 317.4

t = 20

A = 10,149

t = 100

A = 1.1 x 1012

                        

  1. A = 1,000

t = 9.968

A = 10,000

t = 19.936

A = 1,000,000

t = 39.872

At first both functions were used in order to find the results. However as the difference between the first function (A = ) and the second (A = )) was slightly different, the latter was used instead due to the fact that it is more accurate. In the second function we deal with the constant e, which has the value of approximately 2.718, and on the first function this value is rounded up to 2, making it more inaccurate. Therefore it is reasonable to use the second function, as e is not being rounded up, thus leading to more accurate results.

The graph of A does not represent the actual growth pattern of the bacteria population, since it does not take into consideration two main important factors which affect the rate. Firstly, the death rate is not taken into account, thus affecting the rate of growth and the final result of the population. Not all bacteria survive, and so not all bacteria reproduce. For it to be accurate and fair, a percentage would need to be calculated regarding death rate, and so a new function would have to be created. Secondly, the graph also ignores the maximum limit the population can reach. The population can not reproduce forever; it will reach a limit and then remain constant. If both of these factors were taken into consideration, the graph would then represent the actual growth of the bacteria population.

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a)         t = 9.973

b)        t = 19.937

        

c)        t = 39.894

        3.        

  1. Table 2:

  1. A = )(0.8t/3)

The original function from 2(b) was used as a constant, since it represents the part in which the population is being doubled. Once this is established, the death rate (0.8t/3) then was added into the equation. This has no effect on the final result for it makes no difference whether the population is being doubled first and the death rate later, or ...

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