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Introduction

Chemistry TAS Report 1. Experiment Number : 5 2. Date : 05/11/2007 3. Title : An Investigation of the Order of the reaction of Iodine with Propanone 4. Aims/Objective : To determine the order of the reaction of Iodine with Propanone. 5. Introduction / Theory: This reaction is first order with respect to propanone and first order with respect to the hydrogen ions which the reaction is catalyzed by. The order with respect to iodine can be determined by having a reaction mixture which the initial concentrations of propanone and hydrogen ions are very much larger than that of iodine. And only the concentration of the iodine is varied during the reaction and thus its effect on the reaction rate can be seen. The above reaction can be followed by monitoring the concentration of iodine. The steps, samples from the reaction mixture from time to time are removed and these are analyzed for iodine, are involved. ...read more.

Middle

0.0 5.0 10.0 15.0 2. 50.0 cm3 OF 0.02 M iodine solution was added by measuring cylinder to the propanone mixture as quickly as possible. Stop watch was started at the same time. And the content was mixed. 3. During the 5 minutes interval , 10.0 cm3 of the 0.5 M sodium hydrogencarbonate solution was measured and then added into another conical flask . 4. After 5 minutes, 10.0 cm3 of the reaction mixture was pipetted into the conical flask prepared in step 4. When it was done, the time should be noted. 5. The solution in step 4 was mixed and then titrated with 0.01 M sodium thiosulphate(VI) solution. Starch solution was used as indicator. 6. After 10, 15, 20, 25 and 30 minutes, 10 cm3 portions of the reaction mixtures in step 2 were withdrawn and the above procedure was then carried out each time. ...read more.

Conclusion

f) The order of reaction with respect to iodine is zero, i.e. n = 0 g) Iodine does not take part in the rate determining step of this reaction. h) The intercept of the graph with the y-axis is the initial concentration of iodine. i) The concentration of the sodium thiosulphate(VI) solution is 0.01M. 3. Group / Pair No. A B C D Gradient of graph / cm3min-1 - 0.284 - 0.255 - 0.220 - 0.180 [ The required graph please refer to Appendix 2. ] a) The gradient of the graph in Discussion 1 is directly proportional to the rate of reaction and volume of propanone solution is also directly proportional to its concentration. Since a straight line is plotted in the graph above, rate of reaction is directly proportional to the concentration of propanone. Thus, the order of the reaction with respect to propanone is 1. b) Rate equation : Rate=k[CH3COCH3]a[I2]b[H+]c Since b = 0 and [H+] = constant So, rate = k[CH3COCH3]1 ...read more.

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