Experiment Objective. To determine the approximate strength of hydrogen bond formed between ethanol molecules by measuring the enthalpy change on mixing it with cyclohexane.

Authors Avatar

Determining the approximate strength of H-bond


Objective
          To determine the approximate strength of hydrogen bond formed between ethanol molecules by measuring the enthalpy change on mixing it with cyclohexane.

Principle
          Ethanol contains ─OH group which can form hydrogen bond among its molecules but cyclohexane hasn't. On mixing, cyclohexane will break the hydrogen bond among ethanol molecules. Breakage of hydrogen bond consumes energy thus the temperature lowers and hydrogen bond strength of ethanol can hence be calculated.

Chemicals
          ethanol, cyclohexane

Apparatus
          10ml pipette, pipette filler, test-tube, cotton wool, thermometer, beaker

Experimental set-up
                  

Procedure
         1.> Weigh a test-tube and the weight is recorded.
         2.> The initial temperature of ethanol, cyclohexane and test-tube are recorded in
Table 1.
         3.> A test-tube is placed into a beaker and is surrounded with cotton wool.
         4.> A thermometer is then put into the test-tube.

         5.> Pipette 4 cm3 of ethanol into the test-tube.
         6.> Pipette about 9 cm
3 of cyclohexane into the same test-tube.
         7.> The mixture is stirred gently & carefully with the thermometer and the lowest temperature is recorded.

       

Results
                              Mass of the test-tube:       14.44      g

                                           Table 1
 shows the temperature change after mixing two substances:

Join now!

                             Table 2  shows the data of the substances:


                             Energy absorbed to break hydrogen bond
                             = energy absorbed from test-tube (E
1) + energy absorbed from ethanol (E2) + energy absorbed from cyclohexane (E3)
                            
                             Energy = mc
△T
                                    E
1 = [14.44 ÷1000].[0.78].[4.2] kJ
                                         = 0.04731 kJ
                                    E
2 = [(0.81.4) ÷1000].[2.44].[1.7] kJ
                                         = 0.01344 kJ
                                    E
3 = [(0.78.9) ÷1000].[1.83].[2.7] kJ
                                         = 0.03469 kJ

                            E = E
1 + E2 + E3
                               = 0.09544 kJ

                            Strength of hydrogen bond of ethanol = E ÷ no. of moles of ethanol
                                                                            = E ÷ [(0.81.4) ÷ 46]
                                                                            = 1.36 kJmol
-1

Precaution
       1.> The test-tube should be used instead of beaker because the smaller ...

This is a preview of the whole essay