How much acid is there in a solution

Authors Avatar

        

How much acid is there in a solution?

When a metal is extracted from its ore, one by-product is sulphur dioxide, which can be used to make more useful by-products such as sulphuric acid. Sulphur dioxide dissolves into water vapour in the atmosphere to make “acid rain”, which contains sulphuric acid and can cause environmental damage.

The sulphuric acid in the solution of “acid-rain” has a concentration of about 0.05 mol-1 and 0.15 mol-1. The task is to find out the exact concentration by using a titration to then find out how much acid is in the solution. This is can only be done by using a solution with a known concentration

The Brønsted-Lowry theory characterises an acid as a proton donor or has the ability to donate H+ ions, whereas a base is a substance that accepts H+ ions. Strong acids and bases are substances that for ions easily in water and in dilute solutions they are made entirely of ions. Weak acids and bases are substances which form solutions which are partially in form of ions.

These curves show the pH change when different concentrations of bases are added to different concentrations of acids and vice versa. The curve that applies to this investigation is the “Strong acid to weak base” curve.

Indicators

Indicators are weak acids which change colours within a certain pH range, for example:

From the titration curves the best indicator to use would be Methyl orange, as the pH range lies on the line, which has the same volume, it should have a distinct colour change from yellow to red. If the other indicators, litmus or phenolphthalein were to be used, the results are likely to be inaccurate as there are a wider range of volumes at which the pH changes at, in relation to the titration curve.

Join now!

As indicators are weak acids, only a few drops are needed, if 5 or 10ml were added, it would cause the solution being titrated to be slightly more acidic and may effect results.

Group I carbonates are highly soluble and are also thermally stable, so they won’t decompose when heated.

The reaction between sodium carbonate and sulphuric acid will be a neutralisation reaction, forming a soluble salt, water and carbon dioxide:

Na2CO3(aq) + H2SO4(aq) → Na2SO4 + H2O + CO2 

The standard solution will be 250ml of 0.1mol-1 of Na2CO3. This will give a known solution, which ...

This is a preview of the whole essay