Investigating the energy released from burning fuels

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Investigating the energy released from burning fuels

Aim: Does the size of the alcohol molecule affect the amount of energy released when burnt?

Combustion

Combustion is the scientific term for burning

The word equation for combustion is fuel + oxygen → carbon dioxide + water + heat  

Prediction

I think the larger the molecule in the alcohol the more energy will be released. To test this I will be doing an experiment that will give off an exothermic reaction, which mean it releases heat. I will then see which alcohol gives of most heat and therefore releases more energy, the alcohol with the larger molecules or the one with the smaller ones.

In the experiment the fuels I will use are Methanol (CH3OH) Ethanol (C2H5OH) Propanol (C3H7OH) Butanol (C4H9OH).

The symbol equations for these when burning are:

Methanol: CH3OH + 1.5 O2 → CO2 + 2H2O

Ethanol:  C2H5OH + 3O2 → 2CO2 + 3H2O

Propanol: C3H7OH + 4.5O2 → 3CO2 + 4H2O

Butanol:   C4H9OH + 6O2 → 4CO2+5H2O

For the reactants to react together the bonds need to break. This uses energy.

Butanol needs the most energy as it is the biggest fuel and has most bonds to break.

We can calculate the total energy required to break the bonds for each fuel and the total energy, which is released from each fuel. Then when we’ve calculated these two we can divide them to get a figure for the overall energy released.

Bond Energy Values

These are how the bonds are formed in each fuel:

Methanol            Ethanol             Propanol                 Butanol        

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Total Energy Needed (To break the Bonds):

CH3OH (Methanol) + 1.5O2 (Oxygen) = Total Energy Needed

3 x 435 + 358 + 464 = 2127 (The Total Bond Energy needed for Methanol)

1.5 x 497 = 745.5 (The Total Bond Energy needed for Oxygen)

2127 + 745.5 = 2872.5 (The Total Energy Needed)

C2H5OH (Ethanol) + 3O2 (Oxygen) = Total Energy Needed

5 x 435 + 358 + 464 + 347 = 3344 (Total Bond Energy needed for Ethanol)

3 x 497 = 1491 (The Total Bond Energy needed for Oxygen)

3344 + ...

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