Investigating the Rates of Reaction for Halogenoalkanes

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Investigating the Rates of Reaction for Halogenoalkanes

Aim

The aim of this experiment is to show how the rate of reaction of the halogenoalkanes changes in respect to the C-X bond, where the C is the carbon and the X is the halogen. This will occur through a nucleophilic attack.

The halogenoalkanes undergo hydrolysis according to the following equation:

CnH2n+1X + OH¯                                 CnH2n+1OH + X¯

Plan
 
The plan for this experiment is to take three different halogenoalkanes and add a nucleophile to each of the halogenoalkanes record and compare my observations for each halogenoalkane experiment. In the experiment, the number of carbons in the halogenoalkene will not vary.
The carbon compound I am going to use will be halogen butane. The nucleophile I am going to use is hydroxide ion (OH
¯). In this experiment I will not use the halogen fluorine because of the strong bond it forms with carbon. According to bond enthalpy the C-F bond is the less reactive of the halogenoalkanes because of how strong the bond energy is between them. The bond energy in the C-F bond is 467 kJ mol-1. So the C-F bond will be too strong to be affect by nucleophiles.

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Equations for nucleophilic substitution reactions are:

C
4H9Br + OH ¯                         C4H9OH + Br¯

C
4H9Cl + OH ¯                         C4H9OH + Cl¯

C
4H9I + OH ¯                             C4H9OH + I¯


Prediction 


My prediction for which bond will react most vigorously with the nucleophile will be the C-I halogenoalkane. This is because it has the lowest bond enthalpy of all the halogenoalkanes. The C-Cl halogenoalkane will be the leased reactive because it ...

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