Modeling a basketball shoot in the lab

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Modelling and investigating the farthest range from which a basketball can be shot into a ring

        

By Janice Lau (U6th)


Content Page

Aim

Background Information

Calculations and Diagram- prove that it’s a parabola

Theory- PROJECTILE MOTION AT AN ANGLE

How to model a basketball shot?

Apparatus

Force vs. Compression – Spring Loaded Plunger

Prediction/Safety

Experiment 1 - Preliminary investigation

Experiment 2

Research about Basketball

Experiment 3

Experiment 4

Experiment 5

Conclusion

Evaluation

Source

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The AIM of my investigation is to find the optimum angle for the maximum range for a basketball shot by modeling it in the lab.

Background- PROJECTILE MOTION

Definition: “An object launched into space without motive power of its own is called a projectile. If we neglect air resistance, the only force acting on a projectile is its weight, which causes its path to deviate from a straight line.”1

The projectile has a constant horizontal and vertical velocity that changes uniformly when it is influence by acceleration and gravity.

Diagram:

Fig 1 &2 shows that basketball shots are projectile motions, however, how can we show it mathematically?

Calculations

Consider the horizontal and vertical motion individually. Initially,

Ux = u cos θ ----- (1)

Uy = u sin θ----- (2)

The horizontal velocity is constant through out the motion, since the acceleration is vertically downwards. At time t, the velocity components are

Vx = Ux = u cos θ ----- (3)

Vy = Uy – gt = u sin θ –gt ----- (4)

The horizontal and vertical displacements of the objects are:

X= Uxt = ut cosθ ----- (5)

Y= Uy – ½ gt2 = ut sin θ – ½ gt2 ----- (6)

From equation (5) we have,

t= x/ u cos θ

Putting t into equation (6), the equation of trajectory is,

y= x tan θ – g/2u2 cos2 θ

This shows that the object can be described as a parabolic path since it is comparable with the equation y= - kx2 + c.


Theory- PROJECTILE MOTION AT AN ANGLE

A general case of projectile motion occurs when the projectile is fired at an angle. y=0;

  1. Upward direction is positive. Acceleration due to gravity (g) is downward thus         g = - 9.8 m/s2

2. Resolve the initial velocity vo into its x and y components:

          vox = vo cos θ                  voy = vo sin θ

3. The horizontal and vertical components of its position at any instant is given by:         x = voxt                        y = voy t +½gt2 

4. The horizontal and vertical components of its velocity at any instant are given by: vx = vox         vy = voy + gt 

                 

5. The final position and velocity can then be obtained from their components.

To find optimum angle for the maximum range,

Therefore, Maximum range is 45° since 2θ = 90°

However, this will only be the theoretical optimum angle when there is no air resistances exist. In the following investigations, I would like to investigate the optimum angle when air resistances exist.


How to model a basketball shot?

         

The general idea of this experiment is to give a constant force on a ball at a certain angle, aiming to land on a sand pit as follow.

Figure 3. The general experimental set up

Apparatus

  • Spring loaded plunger
  • A ‘run way’
  • Lab Jack
  • Clamp and stand
  • A tray of sand
  • Meters ruler
  • Protractor
  • Measurement tape
  • Light gate
  • Table tennis ball

In this experiment, a spring loaded plunger is used to shoot the ball. With the idea of compressing and extending a spring, it creates a force and a velocity to a ball. In order to find this the spring constant and calculate the velocity of the ball, the force to extension gradient has to be found.

Join now!


Investigation about the spring loaded plunger

Figure 4. Finding spring constant experimental set up

Experimental Set up: Fixed the trolley using a clamp and at the same time fix a ruler next to it, then Measure the original length of the spring.

Method: place 50g of mass on the spring increasingly. Record the corresponding length of the spring and calculate the compression of the spring every 50g. From this we can find out the spring constant k in formula F = -kx.

Table 1: Spring constant – Force vs. Compression

Corresponding error is ...

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