Peroxide Investigation

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Sc1 Peroxide Investigation - James Baxter

1AS

Introduction

This experiment will investigate the effect of an environmental factor on the rate of Hydrogen Peroxide breakdown using Peroxidase enzyme in celery. We will be adding Peroxide (H202), which is a toxic product of several different metabolic reactions, to liquefied celery. The peroxidase enzyme in the liquefied celery has a specific active site like every enzyme and the hydrogen peroxide is a substrate that fits the active site of the peroxidase enzyme. Every enzyme as an active site, like a cleft or depression in its side and this enzyme has a substrate or substrates that fit this cleft exactly. In this experiment the interaction of the substrate (hydrogen peroxide) with the active site on the peroxidase enzyme breaks the substrate apart into two different products - water and oxygen. These two product molecules leave the active site, leaving the enzyme molecules unchanged and ready to bond with another substrate molecule.

Hydrogen Peroxide Water + Oxygen

2H202 2H2O + O2

Variables

There are many variables that we could change in the proceedings of our experiment that would change the rate of hydrogen peroxide breakdown and they are as follows: -

) pH - Most enzymes work best at a pH of around neutral (pH 7), however some enzymes have a different optimum pH. Since pH is simply a measure of hydrogen ions and these ions can't interact with the bonding of certain chemicals (for example, amino acids), an enzyme working in a pH very different from its optimum pH will have its bonding interfered with and it will eventually become denatured. We could perform the experiment under a number of different pHs and, keeping all other variables constant, see the effect of pH on the rate of oxygen production, hydrogen peroxide breakdown.

2) Temperature - When temperature is increased, the molecules in a chemical will move faster, thus increasing collisions between the substrate and enzyme, therefore speeding up the reaction. There comes a point however that the molecules are moving so fast that the enzyme becomes fractured and denatured when it collides with the substrate. Also if the temperature is too low there is virtually no molecular movement so no reaction is present. Therefore we could change the temperature in the experiment and record the oxygen production (hydrogen peroxide breakdown) at different specific temperatures.

3) Peroxide concentration - The more substrate molecules there are present in the solution, the more bonding will take place, assuming there are enough enzyme molecules to bond with them, as each substrate will bond with one of these enzyme molecules and so increase the reaction rate compared to when there were fewer substrate molecules. If the peroxide concentration decreases, there will be a decrease in the reaction rate since, assuming there are enough enzyme molecules to bond with, there will be not so many substrate molecules to bond with the enzyme molecules. We could alter the peroxide concentration and record the rate of reaction in accordance to that concentration.

4) Volume of Peroxidase - If the volume of peroxidase is increased there will be more enzyme molecules to bond to the substrate molecules with and so, assuming that there are substrate molecules available, the peroxide breakdown will be increased. However if all the substrate molecules are currently bonding, an increase in peroxidase will not increase reaction rate since the enzymes will not be able to bond, as there are not enough substrate molecules to 'go round'. The reaction therefore will not speed up. Therefore we could change the volume of celery and because the celery has peroxidase in it, this will increase the volume of peroxidase and so we can measure the rate of reaction in accordance to that volume.

5) Stirring - Because stirring increases the speed of the liquid, thus increasing the molecule speed, it therefore increases collisions between the substrate and the enzyme and so increases reaction speed. We could alter the time that we stir the solution and record the amount of oxygen produced at for those particular experiments.

6) Time - Time is a factor that can affect the rate of reaction immensely. If the enzyme and substrate are only allowed to react for a short period of time obviously the overall rate of reaction will be high since enzyme reactions start off fast then slow down later on, and the overall amount of oxygen will be small. If they are allowed to react for a long time, the overall reaction rate will be small since it almost levels out and slows down later on, and the mean average will be therefore smaller than a shorter time. However the total oxygen collected will be much higher than had the reaction been for a shorter time. We could alter the time that we record results for and compare the different average rates of reaction.
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7) Mass - Keeping the other variables and the ratio between enzyme and substrate constant, the mass of the solution, when increased, will cause an increase in total amount of oxygen collected, but not rate of reaction, since the ratio between enzyme and substrate remains the same. If it is decreased, as before the total oxygen collected decreases but the reaction rate remains the same. We could alter the mass and record the different amount of oxygen collected at these different masses, despite the fact that reaction rate would remain the same.

8) Surface Area - Increasing ...

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