physics making sense of data

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        Page         11/3/2008

Making sense of data coursework

The experiment

A ball bearing of mass 28.82 g was rolled down a smooth ramp, which was set at a fixed angle of 5˚. The time was measured and recorded using a stop clock of accuracy 0.01 s. Three times were recorded to improve accuracy.

Results

Analysis

The graph above tells us that as the distance of the ball bearing from the bottom of the slope increases, the time it takes for the ball to reach the bottom will also increase. However, we can also see that the gradient of the graph changes constantly, indicating that this is a non-linear relationship. At the start of the graph, there is a gradient of 9.6 s m-1, but when the distance is approximately 0.8 m, the gradient becomes significantly less at 1.5 s m-1.

As the distance increases, the gradient of the graph decreases. This suggests that the average speed of the ball bearing is increasing.

Gradient     =     ∆y ∕ ∆x     =     t ∕ s

c     =     s ∕ t

1 ∕ c     =     t ∕ s

This would be due to the fact that with a higher distance, there is more time for gravity to accelerate the ball bearing.

The graph shows a typical square relationship, y = k√x - where k is an unknown constant. In this particular circumstance, it shows how distance is directly proportional to time squared, s α t2.

y     =     k√x        

x     =     y2 ∕ k        

s     =     t2 ∕ k        Remove constant to leave only two variables

s     α     t2

It is also possible to derive this relationship from one of the kinematic equations, s = ut + ½at2. In the experiment, the ball bearing always starts from rest, u = 0 m s-1 so s = ½at2.

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s     =     ½at2        The ‘½a’ is the constant in this equation

s     =     kt2        Remove constant to leave only two variables

s     α     t2

Since u = 0 m s-1, the ball bearing must have experienced some force to make it accelerate down the slope. Assuming there is no further human involvement after it has been placed on the smooth slope, the weight of the ball bearing would be the only force constituting to its movement.

m     =     28.82 g     = ...

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