• Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

Planning an experiment to investigate the effect of an enzyme on the rate of hydrogen peroxide breakdown.

Extracts from this document...


Planning an experiment to investigate the effect of an enzyme on the rate of hydrogen peroxide breakdown Aim To investigate the effect of celery extract concentration on the rate of hydrogen peroxide breakdown. Question: What is the most efficient concentration of celery extract enzyme to breakdown the solution of hydrogen peroxide into water and oxygen? Apparatus Hydrogen peroxide solution Celery extract solution Stand Clamp & boss 6 Test tubes Stopwatch Test tube rack 150cm conical flask + bung + tubing + 3 way tap Tubing Through Gas syringe Balance Goggles Labels Hydrogen peroxide Hydrogen peroxide will breakdown to oxygen and water in the presence of catalase. The reaction will increase with increasing enzyme concentration when molecules of hydrogen peroxide are freely available. However, when molecules of the substrate are in short supply, the increase in rate of reaction is limited and will have little effect. Celery extract (catalase) This important enzyme in present in all aerobic tissues (Vines and Rees, 1969). Since hydrogen peroxide is toxic to protoplasm it must be broken down into water and molecular oxygen. ...read more.


Inhibitors therefore slow the rate of reaction. They should not have affected this investigation, however, as none were added. The volume of catalase solution will not be changed as well. So the temperature, inhibition, substrate concentration, and volumes of enzyme are kept constant So that it is a fair test. Method 1. Make the concentration of 20%, 40%, 60%, 80% and 100% of celery extract solution. I want use 4ml of celery extract and 16ml of water as 20% of celery extract solution, 8ml of celery extract and 12ml of water as 40% of celery extract solution, 12ml of celery extract and 8ml of water as 60% of celery extract solution, 16ml of celery extract and 4ml of water as 80% of celery extract solution, and 20ml of celery extract as 100% celery extract solution. Pour each one of the solutions in a test tube, and place them on the test tube rack. To make sure that the concentrations are accurate, a syringe or a measuring cylinder will be used to measure the volume. ...read more.


This allows you to perform the experiment safely and unimpeded care should be taken to ensure that liquid is not spilled onto the floor to cause slippage. Prediction The enzyme molecules have active sites that help them to recognize their substrates in a very specific way. Just like a key only fits into a specific lock, each enzyme has its own specific lock, each enzyme has its own specific substrate. This is called the lock and key theory. The enzymes never actually get consumed in the process; they just increase the rate of reactions. I think the concentration of 100% of enzyme solution will produce 30ml of oxygen gas by the shortest time, because it has more enzyme molecules than other solutions, in the plant the enzyme is undiluted, and therefore the most efficient solution is likely to be 100%. Conclusion A preliminary test was carried out to practice the techniques of measuring small volumes with the syringe and making accurate concentration of enzyme. It was also beneficial, because some problems were encountered with the assembly of the equipments, which would have had a negative effect on the experiment if they had not been detected beforehand. 1 ...read more.

The above preview is unformatted text

This student written piece of work is one of many that can be found in our AS and A Level Molecules & Cells section.

Found what you're looking for?

  • Start learning 29% faster today
  • 150,000+ documents available
  • Just £6.99 a month

Not the one? Search for your essay title...
  • Join over 1.2 million students every month
  • Accelerate your learning by 29%
  • Unlimited access from just £6.99 per month

See related essaysSee related essays

Related AS and A Level Molecules & Cells essays


    So that all the measurements that I take, and all the readings, are accurate to the same degree. CONTROLLED EXPERIMENTS I have decided to carry out some controlled experiments. These shall prove that the factor I am testing, the substrate is what is actually causing saccharomyces cerevisiae to respire and no other external factor such as temperature, pH apparatus etc.

  2. Investigating the break down of Hydrogen Peroxide using celery tissue to supply the enzyme ...

    The volume of celery and water solution was tested because there needed to be a balance between the mass of celery and the volume of water used because the solution had to be the right consistency so that it could be measured accurately in a measuring cylinder and water was

  1. for this experiment my main aim is to investigate the effect of temperature on ...

    > Measure 10cm3 of H2O2 with pipette and pour into the conical flask. > Cut three masses of liver 0.8g, 0.2g, 0.3g. > Place thermometer into conical flask and into beaker, to ensure they have the same temperature. > Prepare stop watch.

  2. To investigate the rate at which hydrogen peroxide is broken down by the enzyme ...

    to very fast particles (high energy). Most of the particles however will be moving at a speed very close to the average. The Maxwell-Boltzmann distribution shows how the speeds (and hence the energies) of a mixture of moving particles varies at a particular temperature(b).

  1. This is an experiment to show how different concentration of celery tissue enzyme, catalase ...

    The hypothesis suggests that when the enzyme's active site comes into contact with the right substrate, the active site slightly changes or moulds itself around the substrate for an effective fit. This shape adjustment triggers catalysis and helps to explain why enzymes only catalyse specific reactions.

  2. The effect of Copper Sulphate concentration on Catalase activity on Hydrogen Peroxide.

    present in all cells, and this accounts for its lethal effect on the body. Catalase being an enzyme is also a protein and therefore it is composed of several structures including a 3D tertiary structure. This is the section of the enzyme, which I am going to focus on, because

  1. Investigate (by experimentation) the effect of substrate concentrations on the rate of the decomposition ...

    Therefore if there are double the amount of substrate molecules in a solution, double the amount of reactions will take place at once and the rate will be doubled. The problem is, because of the time taken for the reaction and dissociation of the enzyme-product complex, as the concentrations of

  2. The Effect Of Substrate Concentrations On The Rate Of The Decomposition Of Hydrogen Peroxide ...

    For low concentrations I think that the rate of the reaction will be directly proportional to the concentration of hydrogen peroxide in the solution. This is because if double the amounts of substrate molecules are in the solution, double the amount will find an enzyme molecule at the same time,

  • Over 160,000 pieces
    of student written work
  • Annotated by
    experienced teachers
  • Ideas and feedback to
    improve your own work