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Report of My Visit to Xscape

On the 6th of February 2004, our Physics class was invited to take a tour of the skiing facility at Xscape in Milton Keynes. The visit gave me a good insight into different areas of Physics that were seen at the skiing complex. We learnt a lot about the cooling system, how it works, and areas of energy loss which could be harnessed instead of lost. We were given a tour as well as a brief talk about Xscape by Mr. Shears.

Section 1: Aspects of Physics Observed

1.1

I observed the operation of drag lifts at Xscape which took skiers back up the ski slope. Each drag lift consisted of 16 hangers onto which the skiers would sit on when going up the ski slope. The cable used to carry all 16 skiers needs to be able to support the 16 skiers by withstanding high degrees of tension. This tension acts on the cable in opposite directions, but these tensions will not equal each other. This is explained below:

I am going to focus on the tensions in the cable for one skier sitting on a hanger being pulled up the ski slope. We were told by Mr. Shears that the cable to the top of the slope is at an angle of about 22° to the horizontal and the cable down to the bottom of the slope was at about 20°. We can find the tensions in the cable by resolving forces acting horizontally and vertically on the cable.

We know that the horizontal component of T1 and T2 must be equal to each other in opposite directions:

T1cos22 = T2cos20        

T2 = T1(cos22÷cos20)                                                                (1)

The vertical component of T1 that acts upwards is equal to the weight of the skier, mg, where m is the mass of the skier and g is the force acting downwards due to gravity plus the vertical component of T2, also acting downwards:

Mass, m=75kg

Gravity=9.81Nkg-1

T1sin22 = mg + T2sin20                                                                 (2)

We can substitute equation (1) into equation (2) to give:

T1sin22 = mg + T1(cos22 ÷ cos20)sin20

T1 = mg ÷ [(sin22) – sin20(cos22÷cos20)] = 1.98X104N

We can substitute T1 into equation (1) to give:

T2 = T1(cos22÷cos20) = 1.95X104N

From these calculations, we can see that the tension acting in the opposite direction is not the same. A cable that is able to withstand a tension of about 20000N acting on it in opposite directions should be used for the drag lifts. We can also see that T1 and T2 cannot be the same because the two angles made by the cable to the horizontal are not equal and therefore one will be greater than the other.

1.2

The cooling system at Xscape effectively uses almost the same cooling process in a fridge freezer but here it is of an industrial scale. The main element of physics that occurs through this system is energy changes. The snow is cooled using a network of pipes that run underneath the snow box. Flowing through the pipes is glycol at temperatures of between -6°C to -14°C. The system works by compressing low temperature glycol gas using electricity. As the glycol compresses work is done on the gas and its volume reduces. There is no heat transfer in this closed system which leads to an increase in the internal energy of the glycol and subsequently increases its temperature, known as adiabatic compression. The liquid then passes through a condenser where the heat is removed as heat energy radiates from the pipes and is taken away by fans and blown outside.

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Future Developments

This part of the process loses a large amount of heat energy which could have been distributed through the use of ducts and fans to other areas of the Xscape complex, such as to the restaurants. Using this heat energy will reduce the complex’s existing heating bill resulting in the business being more energy efficient. In the short term, the introduction of large fans and ducts to the complex may prove expensive, but in the longer term the savings made in heating bills will be able to cover the cost of introducing the ducts and fans.

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