The Effect of Substrate Concentration on the Rate of Decomposition of Immobilised Liver Catalase.

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The Effect of Substrate Concentration on the Rate of Decomposition of Immobilised Liver Catalase

Background Information:

     

When the chemical Hydrogen peroxide (H2O2), is introduced to the enzyme Catalase, it is decomposed into to products, Oxygen (O2) and Water (H2O). This is shown by the equation:

                       2H2O2 (l)                               2H2O (l)  +   O2(G)

AIM:

 

I am aiming to find out whether increasing the concentration of substrate (H2O2) affects the rate at which Oxygen is produced from the decomposition reaction. I will do this by counting the number of bubbles of Oxygen produced from several samples over a set period of time.

I have established that:  The Independent variable = Substrate concn

        The Dependant variable   = Production of O2

The variables:

The variables that have to remain constant are:

  • Concentration of catalase (5% liver extract)
  • Volume of Hydrogen Peroxide
  • PH
  • Temperature (controlled by water bath)
  • Time (2 min. period p/experiment)

PLANNING

I am going to be changing the concentration of H2O2 that the beads of catalase will be added to (making it an immobilised enzyme). Altering the concentration of H2O2 will affect the rate at which the decomposition takes place and therefore the amount of O2 produced.

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     The concentrations that I will be using are:

  1. 10%
  2. 20%
  3. 30%
  4. 40%

I am going to be using a 10ml sample of H2O2 soln in each experiment      

1ml of hydrogen peroxide soln = 10% concn

          9ml = 90% concn

APPARATUS:

  • 2 Boiling tubes, 10ml Measuring cylinder, 2x100cm3 Beaker, Delivery tube, test tube rack, syringe, bottle of distilled water, sieve, 50cm3 beaker, stopwatch.

To make my results reliable, repeat experiment will be done in all ...

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