The main purpose of this experiment was to determine the equilibrium constants of deprotonation reactions of 2-naphthol using UV-Vis and fluorescence spectroscopy.

Authors Avatar by kanaanghadygmailcom (student)

Deprotonation of 2-Naphthol in Ground and Excited States.

Ghady Kanaan
CHE 441- 001
Experiment 5
Lab Partners: Wyatt Ross Ringo, Abby Darpel

Experiment Date: April 6th  , 2021

Submission Data: April 13th  , 2021

Introduction

The main purpose of this experiment is to determine the equilibrium constants and enthalpies of the deprotonation reaction of 2-Naphthol. This experiment dives deep into proving that thermodynamical quantities of a specific compound are correlated to their energy states.

This experiment relies on spectroscopy to determine unknown quantities. An equation that comes to mind that relates energy and light is Einstein’s equation (1):

This equation uses a Plank’s constant, the speed of light, and  which is the wavelength in meters. The value obtained for the equation above is the energy of a photon, in order to obtain the energy per mole of reaction, simply use Avogadro’s number.

Transitions between electronic states rely heavily on the movement of electrons. The energy difference for these valance-shell electrons happens in the ultraviolet and visible light spectrums, hence UV-Vis’s spectroscopy.  Organic molecules are generally in the group electronic state, S0,  (1). With the help of quantum mechanical rules, the electronic excitation from ground state to excited state would be stronger since the states have the same electron spin multiplicity (1). If the energy transition involves photons, S0  S1 upward transition, as seen in Diagram 1, show the absorption of light leading the molecule to be in a higher state. On the other hand, if the molecule shows emission of light, S1  S0, this can be measured with fluorescence. Comparing the different phenomenon, absorption is a one step process while fluorescence is a two-step process because light must first be absorbed to excite the molecule before it can fluoresce (1),(4).

Absorption bands at higher energy correlate to transitions located mostly in the vibrational levels of the ground state at , all the way to vibrational levels at the excited state. As anything with high amounts energy goes, excited states are unstable when compared to ground electronic states. Thus, allowing molecules at excited states to undergo reactions that will allow them to get rid of the excess energy bottled up.

This experiment requires the use of 2-Naphthol, when 2-Naphthol is placed in an aqueous solution, it acts as a weak acid due to the hydroxy functional group present in the compound(3). Recall the weak acid general equation:

Join now!

When 2-Naphthol is placed in an aqueous solution, it exists in equilibrium with and its conjugated base (2):

Diving deeper into 2-Naphthol quantum properties, in its ground electronic state, 2-Naphthol is a singlet under S0. This means that all of the molecule’s electrons are spin-spin paired. In this lab, a deep analyzation of the electronic state transition of 2-Naphtol. Mainly, this lab focuses on the transition from its group state S0 to the first excited state S1 (1). Two different types of spectroscopy will be put to use in this lab. UV-vis absorption spectroscopy will focus on measuring the group ...

This is a preview of the whole essay