2. The DC supply was adjusted to keep the voltage across Nodes A and C to 5V
3. The voltage across the branched that connect to Node B were measured, the data
we took
+
+
=0.1330+(-0.0398)+(-0.0936)=-4x
A
4. Step 3 was repeated for Node M, the data we took
+
+
=0.06643+(-0.1078)=0.03995=-1.42x
A
The results we took both are very close to zero. The above result show that it obey the Kirchhoff’s first law(current law).
5. The voltage across AC was adjusted to 5V, then the voltage around loop AMBCA was measured, the data we took
6. The voltage around loop ABMCA was measured, the data we took
The results we took both are very close to zero. The above result show that it obey the Kirchhoff’s second law(voltage law).
Experiment 2:(Equivalent resistance)
Theory:
The transformation is used to establish equivalence for networks with three terminals. Where three elements terminate at a common node and none are sources, the node is eliminated by transforming the impedances. For equivalence, the impedance between any pair of terminals must be the same for both networks. The equations given here are valid for complex as well as real impedances
Procedures:
The power supply was turned off. And the multimeter was used to measured the equivalent resistance
of the network in the previous circuit we used
=21.5Ω
The power supply was removed, we measured again the equivalent resistance
=28.4Ω
The result in step 1 is smaller than in step 2.In step 1 , the power supply has not been removed, and it consists internal resistance. As it connects parallel to
the circuit, the equivalent resistance will be smaller than without parallel internal resistance.
The star-to delta or the delta –to –star transformation was used to calculate the equivalent resistance of network shown in figure 3.
equivalent resistance of
:
The
we calculate is close to step 1 but smaller than step 2. When we calculate the equivalent resistance of
,we don’t know the internal resistance of power supply and we assumed the internal resistance is zero and ignore it in calculation, so the result we calculate is similar to data with removal of power supply.
Experiment 3(Maximum power transfer theorem)
Procedures:
The circuit as shown in figure 7 with
was connected and the power supply was adjusted to 5V.
The load
from 1KΩ to 25KΩ resistances were varied in small but suitable step. The corresponding values of
and
in each step were recorded.
=5KΩ
The power delivered to the load against
was plotted
Maximum power: 1.275 mW
4.88
Total resistance:4.88+5=9.88
=10KΩ(with
varying from 5KΩ to 15KΩ)
Maximum power: 0.6127mW
9.2
Total resistance:9.2+10=19.2
=20KΩ(with
varying from 15KΩ to 25KΩ)
Maximum power: 0.0215mW
20.05
Total resistance:20.05+20=40.05
Discussion:
aI) minimum sources voltage:
V=400x2x
=40v
aII) there is not significant risk of this type of accident to occur, as the voltage of personal computer is 17v, it is smaller than the minimum source voltage that can produce electrical shock.
b) The criterion for maximum power transfer from a source to a load is the load resistance equals to the internal resistance of the source. If we are free to select
without changing the source voltage, we can decrease the
in order to maximize the power delivered to the load.
E=i(R+
iE=
=
=
The smaller the
, the higher the power supply
C)
=
=
=
The maximum power output occurs when
=
=0
=0
=2R
=
The maximum power output
=
=