Nutrition for sport.

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Brendan King

There are some nutrients that the human body cannot do without, nutrients that are essential for everyday life, and maintaining a healthy lifestyle. The requirements for each persons specific needs are different depending on the type of training you are doing, your sporting needs, or if you do no training at all.

For example an athlete training for sport where muscle mass plays an importance (weightlifting, boxing), there are needs for a high intake of proteins in tandem with the right kind of training, which will build muscle effectively.

An athlete training for an endurance event such as long distance running/marathons will require a high amount of carbohydrates in their daily diet, preferably complex carbohydrates such as pasta and potatoes, giving a slow burning release of energy.

The everyday person’s diet, a person perhaps not training specifically but recreationally will require a healthy balance of all the basic nutrients:

  • Carbohydrates – approx 60% of diet
  • Fats -  approx 25-30%
  • Proteins – approx 12-15%
  • Vitamins
  • Minerals
  • Water
  • Fibre

In this assignment I have taken my own food diary for one week, along with three other people, each with their own dietary needs in accordance with their weekly quota of activity as well as each persons BMR (basal metabolic rate) and their PAR (physical activity ratio).

Basal metabolic rate

Is the rate at which each subject burns calories during the day whilst resting, performing no activity or exercise.

It is generally worked out by the formula:

Weight of subject in kg x hours in the day

My BMR for example would be 87 x 24 = 2088 kcal

Physical activity ratio

This indicates the rate at which you burn calories, and the amount of calories that you burn whilst performing tasks, sometimes relevant to a subjects training or as mentioned before at a recreational level.

This physical activity ratio is based upon the subject’s body weight, a subject with a heavier body weight working at the same intensity as a subject with a lesser body weight will usually burn calories at faster rate if the period of activity is also the same.

In each subject food diary the amounts of nutrient intake each day is measured in grams, with nutritional value of each meal on food labels produced on packaging. These amounts of nutrients in grams, in order to be calculated must be converted into calories for the benefit of later calculations.

This is done by taking the intake of each nutrient and multiplying the number (in grams) for each day or week, by the amount of calories per gram of nutrient.

  • e.g. 1g of carbohydrate carries 3.75 calories
  • 1 g of protein = 4 calories
  • 1g of fat = 9 calories

Subject 1

Subject 1 has a body weight of 50 kg

Therefore subject one has a BMR of:

50 x 24 = 1200 kcal

for the week therefore 1200 x 7(days) = 8400 kcal

the PAR of subject 1 works out as;

activity                        kcal/min                duration(mins)                total kcal

       

football                6.1                        180                        1098                

typing                        1.4                        120                        168

football                6.1                        60                        366

                

                                                                total = 1632 kcal

Therefore the total energy requirements = BMR + PAR

8400 +1632 = 10032 kcal

To find the energy requirement for one day 10032 / 7 = 1433 kcal

in order to find the requirements for each nutrient intake we must take the recommended % intake for carbohydrate, fats and proteins and multiply it by the total energy required (BMR + PAR) = amount of nutrient in kcals

Carbohydrates = 1433 x 60(%) / 100 = 860 kcals

Fat = 1433 x 25 / 100 = 358 kcals

Protein = 1433 x 15 / 100 = 215 kcals

To convert into grams we multiply these numbers by the calorific content of a single gram of each nutrient

Therefore:

Carbohydrate – 860 (kcals) / 3.75 (calories per g) = 229g

Fat – 358 / 9 = 40g

Proteins – 215 / 4 = 54g

By adding the intake of the nutrients in grams for each day, we can now compare the guideline intake for subject 1, for carbohydrates, fats, proteins and water, according to the BMR and PAR.

For carbohydrates, the actual intake is 586.42 grams,

Therefore for 1 day:

586.42 / 7 = 84g of carbohydrates

To convert this amount to calories:

84 x 3.75 = 315 Kcal

To convert this to a percentage of the daily intake, we must divide the 315 Kcal by the average calorie intake for each day:

3832 / 7 = 547 Kcal

315 / 547 x 100 = 57%

This same set of calculations can be applied to the intake of fats and proteins of subject 1. In the case of fat:

Total intake for the week = 136g

136 / 7(days) = 19g/day

1g of fat = 9 cals

therefore: 19 x 9 = 171 Kcal

Again, we divide the calorific content of the fats by the average Kcal intake per day for fat percentage:

171 / 547 x 100 = 31%

For protein:

Total intake = 157.818 / 7 = 23g

1g of protein = 4 Kcal

so: 23 x 4 = 92 Kcal

To be expressed as a percentage of the diet:

92 / 547 x 100 = 17%

These percentages when added together suggest a discrepancy (57 + 31 + 17 = 105%). The reason for this may be the record of Saturday’s diet. We can see that a McDonalds’ burger, although recorded in energy and carbohydrate, has an undisclosed amount of fat. There is an unusually high ratio of fat : energy content in such foods as chips (Saturday; 16g of fat / 440 Kcal) and chicken in breadcrumbs (Saturday; 13g of fat / 229 Kcal). Tuesday’s diet, which consisted of 3 x potato with a high amount of fat (12.2g), but a low amount of energy in comparison (56 Kcal).

In terms of energy consumption, the requirements for subject 1 are approx. 1433 Kcal / day (BMR + PAR), whereas the actual consumption is a mere 547 Kcal, there should be, therefore, a higher energy / calorie intake with a lower intake of fats. this can be achieved by eliminating needlessly fried foods – the frying tending to add fatty content to an otherwise nutritious base (hash browns).

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Due to the intensity of subject 1’s weekly calorie needs (4 hours of football), the 57% of carbohydrate content needs to probably exceed the 60% guideline to maintain a high level of performance.

Subject 2

Subject 2 has a bodyweight of 50 kg, so BMR = 50(kg) x 24 (hours) = 1200 Kcal

For the week:

1200 x 7 = 8400 Kcal

The PAR for subject 2 is:

Activity                Duration                Kcal / min                Total

Walking                100 mins                4.1                        410

Cleaning                240 mins                3.1                        744

Football                  90 mins                6.1                        549

Walking                120 mins                4.1                            492

                                                                          ...

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