Step 1. x (x + 44)
Step 2. (x + 4)(x + 40)
Step 3. (x2 + 44x + 160) – (x2 - 44x) Difference = 160
Sequence Prediction
The results from each square investigation show a sequence forming. I will demonstrate this in the following table:
I will continue this investigation by finding out the product difference of a 6 x 6 square along with a 7 x 7 square. I predict that the product difference of a 6 x 6 square will be 250, and that a 7 x 7 square will be 360.
6 x 6 Square
- 1 x 56 = 56 6 x 51 = 306 Product difference = 250
- 33 x 88 = 2904 38 x 83 = 3154 Product difference = 250
Algebraic Equation = (x2 + 66x + 250) – (x2 – 66x) Difference = 250
7 x 7 Square
- 4 x 70 = 280 10 x 64 = 640 Product difference = 360
- 32 x 98 = 3136 38 x 92 = 3496 Product difference = 360
Algebraic Equation = (x2 + 77x + 360) – (x2 – 77x) Difference = 360
The calculations show that my prediction was correct. Using this sequence pattern, I will calculate the 8th and 9th term of the number grid:
Looking closely at this table, I can see a formula for finding the nth term (n). Multiplying 10 by n2 will provide the product difference for any nth term in a 10 x 10 number grid.
Nth Term = 10n2.
3rd Term: 10 x 32 = 90
6th Term: 10 x 62 = 360
9th Term: 10 x 92 = 810
Further Investigation
The investigation of various sized squares in a 10 x 10 number grid has provided me with an algebraic and nth term formula. I am going to investigate further using different sized number grids, following the same rules of the 10 x 10 number grid, for example: 8 x 8 and 9 x 9 number grids. My prediction is that by multiplying the nth term by the size of the grid, the product difference will be calculated. For example: finding the 3rd term in a 8 x 8 grid, Formula = 8n2, and finding the 5th term in a 9 x 9 grid, Formula = 9n2.
8 x 8 Number Grid
2 x 2 Square
- 1 x 10 = 10 2 x 9 = 18 Product difference = 8
- 3 x 12 = 36 4 x 11 = 44 Product difference = 8
- 36 x 45 = 1620 37 x 44 = 1628 Product difference = 8
I predict that for any 2 x 2 square in an 8 x 8 number grid, the product difference will always be 8. I will prove this theory by using an algebraic equation.
Step 1. x (x + 9)
Step 2. (x + 1)(x + 8)
Step 3. (x2 + 9x + 8) – (x2 - 9x) Difference = 8
3 x 3 Square
- 1 x 19 = 19 3 x 17 = 51 Product difference = 32
- 35 x 53 = 1855 37 x 51 = 1887 Product difference = 32
- 46 x 64 = 2944 48 x 62 = 2976 Product difference = 32
I predict that for any 3 x 3 square in an 8 x 8 number grid, the product difference will always be 32. I will prove this theory by using an algebraic equation.
Step 1. x (x + 18)
Step 2. (x + 2)(x + 16)
Step 3. (x2 + 18x + 32) – (x2 - 18x) Difference = 32
4 x 4 Square
- 4 x 31 = 124 7 x 28 = 196 Product difference = 72
- 26 x 53 = 1378 29 x 50 = 1450 Product difference = 72
- 37 x 64 = 2368 40 x 61 = 2440 Product difference = 72
I predict that for any 4 x 4 square in an 8 x 8 number grid, the product difference will always be 72. I will prove this theory by using an algebraic equation.
Step 1. x (x + 27)
Step 2. (x + 3)(x + 24)
Step 3. (x2 + 27x + 72) – (x2 - 27x) Difference = 72
5 x 5 Square
- 4 x 40 = 160 8 x 36 = 288 Product difference = 128
- 11 x 47 = 517 15 x 43 = 645 Product difference = 128
- 27 x 63 = 1701 31 x 59 = 1829 Product difference = 128
I predict that for any 5 x 5 square in an 8 x 8 number grid, the product difference will always be 128. I will prove this theory by using an algebraic equation.
Step 1. x (x + 36)
Step 2. (x + 4)(x + 32)
Step 3. (x2 + 36x + 128) – (x2 - 36x) Difference = 128
Sequence Prediction
The results from each square investigation show a sequence forming. I will demonstrate this in the following table:
Looking closely at this table, I can see a formula for finding the nth term (n). Multiplying 8 by n2 will provide the product difference for any nth term in an 8 x 8 number grid.
Nth Term = 8n2.
3rd Term: 8 x 32 = 72
6th Term: 8 x 62 = 288
7th Term: 8 x 92 = 810
9 x 9 Number Grid
2 x 2 Square
- 1 x 11 = 11 2 x 10 = 20 Product difference = 9
- 24 x 34 = 816 25 x 33 = 825 Product difference = 9
- 47 x 57 = 2679 48 x 56 = 2688 Product difference = 9
I predict that for any 2 x 2 square in a 9 x 9 number grid, the product difference will always be 9. I will prove this theory by using an algebraic equation.
Step 1. x (x + 10)
Step 2. (x + 1)(x + 9)
Step 3. (x2 + 10x + 9) – (x2 - 10x) Difference = 9
3 x 3 Square
- 1 x 21 = 21 3 x 19 = 57 Product difference = 36
- 29 x 49 = 1421 31 x 47 = 1457 Product difference = 36
- 51 x 71 = 3621 53 x 69 = 3657 Product difference = 36
I predict that for any 3 x 3 square in a 9 x 9 number grid, the product difference will always be 36. I will prove this theory by using an algebraic equation.
Step 1. x (x + 20)
Step 2. (x + 2)(x + 18)
Step 3. (x2 + 20x + 36) – (x2 - 20x) Difference = 36
4 x 4 Square
- 4 x 34 = 136 7 x 31 = 217 Product difference = 81
- 24 x 54 = 1296 27 x 51 = 1377 Product difference = 81
- 37 x 67 = 2479 40 x 64 = 2560 Product difference = 81
I predict that for any 4 x 4 square in a 9 x 9 number grid, the product difference will always be 81. I will prove this theory by using an algebraic equation.
Step 1. x (x + 30)
Step 2. (x + 3)(x + 27)
Step 3. (x2 + 30x + 81) – (x2 - 30x) Difference = 81
5 x 5 Square
- 4 x 44 = 176 8 x 40 = 320 Product difference = 144
- 11 x 51= 561 15 x 47 = 705 Product difference = 144
- 39 x 79 = 3081 43 x 75 = 3225 Product difference = 144
I predict that for any 5 x 5 square in a 9 x 9 number grid, the product difference will always be 144. I will prove this theory by using an algebraic equation.
Step 1. x (x + 40)
Step 2. (x + 4)(x + 36)
Step 3. (x2 + 40x + 144) – (x2 - 40x) Difference = 144
Sequence Prediction
The results from each square investigation show a sequence forming. I will demonstrate this in the following table:
Looking closely at this table, I can see a formula for finding the nth term (n). Multiplying 9 by n2 will provide the product difference for any nth term in a 9 x 9 number grid.
Nth Term = 9n2.
3rd Term: 9 x 32 = 81
5th Term: 9 x 52 = 225
8th Term: 9 x 82 = 810
Summary
The results from this investigation show that for any size number grid there is a working formula to find out the product difference of any sized square. I conclude that the formula for finding out the product difference in a 10 x 10 square is 10n2, a 9 x 9 square is 9n2 and an 8 x 8 square is 8n2. These results suggest that for any size number grid, a formula for finding out the product difference will be the size of the grid, multiplied by the nth term/square size and then squared. For example:
Grid size = G
Nth Term/Square Size = N
Formula = GN2
Further Investigation
I am going to carry on with this investigation, using the same rules as before but instead of examining squares, I will examine rectangles. I will begin this investigation using a 10 x 10 number grid.
2 x 3 Rectangle
- 1 x 22 = 22 2 x 21 = 42 Product Difference = 20
- 13 x 34 = 442 14 x 33 = 462 Product Difference = 20
- 48 x 69 = 3312 49 x 68 = 3332 Product Difference = 20
2 x 4 Rectangle
- 2 x 33 = 66 3 x 32 = 96 Product Difference = 30
- 33 x 64 = 2112 34 x 63 = 2142 Product Difference = 30
- 69 x 100 = 6900 70 x 99 = 6930 Product Difference = 30
2 x 5 Rectangle
- 4 x 45 = 180 5 x 44 = 220 Product Difference = 40
- 46 x 87 = 4002 47 x 86 = 4042 Product Difference = 40
- 51 x 92 = 4692 52 x 91 = 4732 Product Difference = 40
These results suggest that for every rectangle in the 2 x X series the product difference will increase in size by 10. I will test this theory by investigating two more rectangle sizes of 2 x 6 and 2 x 7. I predict that the product difference of a rectangle size of 2 x 6 will be 50 and that a 2 x 7 rectangle will be 60.
2 x 6 Rectangle
- 2 x 53 = 106 3 x 52 = 156 Product difference = 50
- 35 x 86 = 3010 36 x 85 = 3060 Product difference = 50
2 x 7 Rectangle
- 16 x 77 = 1232 17 x 76 = 1292 Product difference = 60
- 39 x 100 = 3900 40 x 99 = 3960 Product difference = 60
My prediction is correct. This provides me with two working formulas for working out the nth term (N) and product difference of any 2 x X rectangle in a 10 x 10 number grid. The formula for working out (N) is:
(N + 1) 10
3rd Term = (3 + 1) x 10 = 40
5th Term = (5 + 1) x 10) = 60
The formula for working out the product difference is:
Length (L) (L – 1) 10
2 x 5 Rectangle = (5 – 1) x 10 = 40
2 x 8 Rectangle = (8 – 1) x 10 = 70
I will now investigate this further, using rectangles of various sizes. For example: 3 x X series and 4 x X series.
3 x 4 Rectangle
- 3 x 35 = 105 5 x 33 = 165 Product Difference = 60
- 15 x 47 = 705 17 x 45 = 765 Product Difference = 60
- 57 x 89 = 5073 59 x 87 = 5133 Product Difference = 60
3 x 5 Rectangle
- 4 x 46 = 184 6 x 44 = 264 Product Difference = 80
- 42 x 84 = 3528 44 x 82 = 3608 Product Difference = 80
- 58 x 100 = 5800 60 x 98 = 5880 Product Difference = 80
3 x 6 Rectangle
- 4 x 56 =224 6 x 54 = 324 Product Difference = 100
- 44 x 96 = 4224 46 x 94 = 4324 Product Difference = 100
- 27 x 79 = 2133 29 x 77 = 2233 Product Difference = 100
These results suggest that for every rectangle in the 3 x X series the product difference will increase in size by 20. I will prove this theory firstly by showing a table with further results, followed by a sequence formula.
My prediction is correct. This provides me a working formula for working out the nth term (N) and the product difference of any 3 x X rectangle in a 10 x 10 number grid. The formula for working out (N) is:
(N + 1) 20 + 20
3rd Term = (3 + 1) x 20 + 20 = 100
5th Term = (5 + 1) x 20 + 20 = 140
The formula for working out the product difference is:
Length (L) (L – 1) 20
3 x 6 Rectangle = (6 – 1) x 20 = 100
3 x 9 Rectangle = (9 – 1) x 20 = 160
By examining these results I predict that in the 4 x X series the product difference will be 30.
My prediction is correct. I will prove this by showing calculations of these examples.
4 x 5 Rectangle
- 1 x 44 = 44 4 x 41 = 164 Product Difference = 120
4 x 6 Rectangle
- 3 x 56 = 168 6 x 53 = 318 Product Difference = 150
4 x 7 Rectangle
- 34 x 97 = 3298 37 x 94 = 3478 Product Difference = 180
4 x 8 Rectangle
- 26 x 99 = 2574 29 x 96 = 2784 Product Difference = 210
These results provide me with a formula for working out (N) in this series:
(N + 1) 30 + 30 +30
4th Term = (4 + 1) x 30 + 30 + 30 = 210
6th Term = (6 + 1) x 30 + 30 + 30 = 270
The formula for working out the product difference for any rectangles in this series will be:
(L – 1) 30
4 x 6 Rectangle = (6 – 1) x 30 = 150
4 x 9 Rectangle = (9 – 1) x 30 = 240
Further Investigation
The results from these investigations have provided me with working formulas for both the Nth Term and product differences of squares and rectangles in the 100 number grid. I predict that there is a formula for finding the product difference for any size rectangle and number grid. My investigations have shown that for every rectangle (L – 1) occurs, I now need to work out the remaining part of the rule. By examining my previous investigations it shows that if I minus 1 from the width and multiply it by 10 it will provide me with the sequence difference. I predict that the (x 10) rule is linked to the grid size of 10 x 10. From this I can start building a formula using the following expressions:
Grid (G)
Length (L)
Width (W)
Differerence (D)
Therefore if (L-1) works, and so does (W-1) 10, I can compose a formula for any size rectangle:
Formula = (L-1) (W-1) G = D
Conclusion
The results from the 100 number grid investigation have proven that my predictions have been correct throughout this study. I have found working formulas for finding the Nth Term (N) and the product difference (D) of both squares and rectangles in a 100 number grid.
To find (N) of a square = GN2
To find (D) of a rectangle = (L-1) (W-1) G
As well as the above formulas I have been consistent in finding algebraic equations for each square and rectangle in a number grid.
If I were to carry this investigation further, I would change the rules with regard to multiplication. I would investigate using addition and subtraction or try using other shapes, such as a stair pattern.