The median is in between £9995 and £11800, so to get the correct figure the two number will be added together and divided by two as there only two number.
£9995 + £11800/2= £10897.5
Mode
There was no most occurring value, this is probably because the items being sold are cars and cannot be the same price also the price varies on how old the car is.
Range
The highest value of a car is £17780 and the lowest price of a car is £6590, this will be subtracted to give the range
£17780-£6590, =£11190
Depreciation
Depreciation in the Oxford school dictionary means “make or become lower in value”, prices of cars depreciate every year as the car itself gets older and is no longer up to customer satisfaction. The value of the car may go down for the reason that the car is getting older in years. Whether if the car has done many mileage or not the car of the price will go down, using the evidence provided car number 31 a Seat Ibiza was £5995 when new and depreciated to £795 because of mileage and the age of the car. The price of the car may also depreciate because of the service history and the owners of the car, the more owners the less the price of the car.
The next car chose was Nissan.
Mean-Nissan (new)
£7995, £6295, £5340, £7799, £12590/5=£8003.80 is the mean of all five Nissan cars.
Median
£5340, £6295, £7799, £7995 and £12590, the median value of all five Nissan cars are £7799.
Mode
Again there was no occurring mode.
Range
£12590-£5340= £7250
The last car chosen from the evidence provided was Rover, but this the old price of the car.
Mean
£22980, £21586, £13586, £8595, £6645, £9695, £24086, £17795, £19530, £14486, £5495/11= £14952.63.
Median
£5495, £6645, £8595, £9695, £13586, £14486, £17795, £19530, £21586, £22980, the median of the old Rover cars is in between £13586 and £14486, these two numbers will be added and divided by two.
£13586 + £14486/2=£14036.
Mode
Again there was no occurring mode.
Range
£22980-£5495=£17485
Pictogram
I will be using a pictogram to show the number of cars using pictures of cars. The cars selected were Volkswagen, Daewoo, Citroen, Renault and Peugeot. One picture of the car represents 2 cars.
The type of car will first be shown on a tally table then it will be shown on a bar graph. The picture below shows the tally graph of how many different types of cars there are.
The information above will be put onto a bar graph, which will look like the bar graph below.
The same information will also be shown on a pie chart:
The next set of cars chosen at random were Nissan, Volkswagen, Daewoo, Honda and Mercedes Benz, the information about the cars was put onto bar graph and pie chart
Now I will be looking at how many cars there of the same make and model, the first one I will be looking at is Ford, the data of the different makes of the same model are put into a tally chart.
The next set of cars was shown on a Bar graph the data will be first put onto to a table.
Without reading the tally table, on the bargraph we can see that there are 12 Vauxhall cars, 3 of Peugeot, Daewoo and Citroen cars and 2 Mitsubishi.
Again the total number of cars were taken and placed on a bar graph, but first the information was placed in a table
Now I will be looking at how many cars there of the same make and model, the first one I will be looking at is Ford, the data of the different makes of the same model are put into a tally chart.
This data will be on a pie chart, I will find the angle by divided the total number of cars by 360, as 360 is the total angle of a whole circle.
360/16=22.5
Now I have to times 22.5 by the number of cars.
I will then add up all the angles to make sure they add up to 360
The following data will now be ready to be put on to a pie chart
The following data was also put on to a bar graph.
A models bar graph to show
The number of Ford
The next make of car I showed information about on was Vauxhall.
This data will be on a pie chart, I will find the angle by divided the total number of cars by 360, as 360 is the total angle of a whole circle.
360/13=28
Now I have to times 28 by the number of cars.
A pie chart to show the
Number of Vauxhall models
This same information will then be put on a graph.
A bar graph to show
The number of Vauxhall models
The third type of car chosen was Nissan
A pie chart to show
The number of Nissan models
The pie chart shows that there are more models of Micra then any other models associated with Nissan. The pie chart also shows that there are an equal number of the remaining models.
The same information will be shown on a bar graph.
A bar graph to show
The number of Nissan models
A scatter diagram showing the Used Price of the car against its age in years:
Now, i am going to investigate the age that effects on the used price for the different makes.
Looking at the scatter diagram above I can say as the older the car was the less it costs to buy, I can say the graph showed a negative correlation.
The next ten cars chosen at random for negative correlation was Vauxhall-Cavalier, Volkswagen-Golf, Renault-Clio, Fiat-Punto, Nissan-Micra, Bmw-316i, Daewoo-Lanos, Ford-Orion, Ford Fiesta and Mitsubshi-Carisma.
This information will then be put onto a scatter diagram.
This scatter diagram shows that as the car gets older in age the price will also drop, this type of scatter diagram has negative correlation.
The next set of car chosen at random was;
From the graph we can see that as the car gets older the price will depreciate, depending on how expensive the car is, for example the car on the graph is 9 years old and is still selling for £14,500.
This graph is negative correlation.
The next ten cars chosen at random for negative correlation was Vauxhall-Cavalier, Volkswagen-Golf, Renault-Clio, Fiat-Punto, Nissan-Micra, Bmw-316i, Daewoo-Lanos, Ford-Orion, Ford Fiesta and Mitsubshi-Carisma.
This information will then be put onto a scatter diagram.
This scatter diagram shows that as the car gets older in age the price will also drop, this type of scatter diagram has negative correlation
The last set of car chosen at random was;
This correlation graph also shows negative correlation.
A scatter diagram showing the old Price of a car against its Mileage:
From the scatter diagram above there is no correlation, this would mean that that the old Price of a car and its Mileage are not related to one another and have no affect on each other.
The next cars chosen to use against no correlation were;
This graph no correlation, the reason why it show no correlation is because the price and the mileage of the car have no relation with each other.
The next set of cars chosen was;
The last set of cars chosen was;
This scatter graph shows no correlation.
Cumulative frequency
Cumulative frequency means “adding it up as you go along”.
the following on the table shows the cumulative frequency.
Inter quartile= upper quartile- lower quartile
Upper quartile =3/4 (n+1)
Upper quartile = ¾ (75+1)
= ¾ (76)
= ¾ *76
= 228/4
= 57
Lower quartile = ¼ (n+1)
= ¼ (75+1)
= ¼ (76)
= ¼ * 76
= 19
Inter quartile = 57- 19
= 38