Maths algerbra

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Maths coursework

In  this coursework we were asked to find the differences in a simple fraction pattern. We had ;

I will look at the differences between the fractions and search  for any general rules. I will apply my good algebraic skills to help find any rules.

I then had to find the differences by taking the fractions away from each other. To find my first difference I had to ;

D1 = difference one

Fraction         2nd-1st                 3rd-2nd                4th-3rd 

D1                  1st                               2nd                              3rd 

I had to take away 2/3 form  1/2 but the  denominators were not the same, so I found the lowest common multiple  from each and multiplied them top and bottom eg.

X2   2   -     1   X3

X2   3         2   X3

        The lowest common  multiple is 6 so I multiplied  2/3 by 2 and 1/2 by 3. I then got ;

4/6 -  3/6 which then equalled 1/6, which was my 1st difference.

I done the same to 3/4 -  2/3             9/12 – 8/12 which equalled 1/12 and my second difference.

I shall begin to search for an algebraic rule for the first differences

To find the nth term I had to take away the n+1th term away from the nth term ;

n+1   – n

n+2     n+1

I made the denominators the same and got ;

(n+1)(n+2)  -     n(n+2)

(n+1)(n+2)     (n+1)(n+2)

I then multiplied the brackets out by completing the square. For the numerator

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(n ² + 2n + 1) – (n ² - 2n)

           (n + 1)  X  (n + 2)

I then cancelled out some of the numerators to get ;

 (n ² + 2n + 1) – (n ² - 2n)

           (n + 1)  X  (n + 2)

so my formula for the first difference was

        1

           (n ...

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