T-total Investigation

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Zakwan Ahmed

                                                             10 A        

Maths Coursework

Mr Uddin

                                                T-total Investigation

Aim:  Find a rule connecting the T-total and the T- number.

 

Investigation- Part one:

(A,B,C)

Investigation- Part Two:

   

Investigation- Part Three:

       

                   3

I placed the 3by2 T on the beginning of the 10by10 grid.

 I then moved the T along the 10by10 grid 3 times in order to find a pattern. These are the 3 positions in which I put my 3by2 T on:

Position 1:                                          Position 2:                     

 Position 3:

The bottom number of the T is always the T-number. I added all the numbers inside the T- shape for each position and this gave me the T- total for e.g. for the first position 1 + 2+ 3+12+22 =40 and this is the T-total for the first position. I then put the T-no of each position in one column and the T-total of each position in another column to see the difference between the T- no’s and the T-totals.

 

    T-no                        T-total

       22                             40       position 1

+1                              + 5                        

       23                             45       position 2

+1                              + 5

      24                             50         position 3

I saw that the difference between the T-no’s is 1 and the difference between the T-totals is 5. The first part of my formula is therefore 5T. It is 5T because that is how many numbers inside the T. I multiplied the difference between the T-total which is 5 by the T-no. Underneath is my working out:

  1. x  5 =110
  2.  x  5=115
  3. x  5=120

I then took away the T-total numbers so that I could find the difference between the T-no and the numbers in each of the 4 squares inside the T.

    110- 40 =70

    115- 45 =70

    120- 50 = 70

I found out that the difference is 70. We get 70 because it is the total of the differences between the T-no and the numbers in each of the other 4 squares. This is the next part of my formula. My formula is now 5T-70

I found out that my formula is correct.

Using expressions I found out that my formula 5T – 70 is correct.

I will now work out the formula for the given 3by2 T on a 9by9 grid.

I placed the 3by2 T on the beginning of my 9by9 grid.

I then moved the T along 3 times in order to find a pattern. These are the 3 different positions in which I put my 3by2 T on:

Position 1:                                     Position 2:

 

Position 3:

The bottom number of the T is the T-no. I added up all the numbers inside the T for each position which gave me the T-total. I put the T-no in one column and the T-total in the other.

 

      T-no                           T-total

       20                                37        position 1

1                               5

       21                                42        position 2

1                               5

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       22                                 47       position 3

I saw that the pattern between the T-no was 1 and the pattern between the T-total is 5 and so therefore 5t is the first part of my formula. I then multiplied the T-no by 5 and then took away the T-total from the answer. I found out that the difference is 63. We get 63 because it is the total of the difference between the T-no and the number in each of ...

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