Plan: I planned to use 9 different Form groups from Year Ten at my School, and all nine were chosen at random. From those clusters, 10 students would be chosen at random once again, from which there would be 5 male and 5 female students, totalling to 90 results, which I believed would me more than sufficient to prove/disprove my hypothesis. The exact same questionnaire sheet would be handed to every chosen one, who would have to turn it in ass soon as possible.
Results: From the 90 Questionnaire that were handed out, only 72 questionnaires came back to and from that only 53 had proper results in them, meaning that they had filled the weight in for both days. This was not what I had expected, but I went to work with it. Results are also attached.
Data Interpretation:
MALE STUDENTS
Mean= Sum of Weight ÷ Number of Heights
i.e. M= (12+8) ÷2
M= 10
Median= (Number of Heights + 1) ÷ 2
5.67 6.00 7.33 9.33 9.67 10 10 10.33 10.67
M= (9 + 1) ÷ 2
M= 5
Median is the Fifth number so 9.67 is the median for Monday
Upper Quartile = 10.17
Lower Quartile = 6.67
Interquartile Range = 3.5
4.33 4.33 5.00 5.33 7.33 7.33 8.67 9.00 10.00
M= (9+1) ÷ 2
M= 5
Median is the Fifth number so 7.33 is the median for Thursday
Upper Quartile = 8.84
Lower Quartile = 4.72
Interquartile Range = 4.12
Standard Deviation = √(∑x2 ÷n)-(∑x÷n)2
Standard Deviation = √(723/9)-(79*9)
= √80.34-8.78
= √71.56
Monday = 8.46
Standard Deviation = √(454.54/9)-(61.42/9)
= √50.5-6.82
= √43.68
Thursday = 6.61
From these results you can immediately see that for Male Students in Year ten, the Weight of their Bags is Heavier on Monday than Thursday, also which the attached graphs and charts display.
Female Students
Mean= Sum of Weight ÷ Number of Heights
i.e. M = (2+3+6) ÷ 3
M = 11 ÷ 3
M = 3.67
Median= (Number of Heights + 1) ÷ 2
3.33 5 5.33 7 7.33 8.67 8.67 8.67 9.33
M= (9+1) ÷ 2
M= 10÷2
M=5
Median is the Fifth number so 7.33 is the median for Monday
Upper Quartile = 8.67
Lower Quartile = 5.17
Interquartile Range = 3.5
3.67 6.66 7.67 8.33 9 9.33 9.33 11.33 11.67
M= (9+1) ÷ 2
M= 10÷2
M=5
Median is the Fifth number so 9 is the median for Thursday
Upper Quartile = 10.33
Lower Quartile = 7.21
Interquartile Range = 3.12
Standard Deviation = √(∑x2 ÷n)-(∑x÷n)2
Standard Deviation = √(698.51/9)-(75.82*9)
= √77.61-8.42
= √69.19
Monday = 8.32
Standard Deviation = √(477.69/9)-(63/9)
= √53.08-7
= √43.08
Thursday = 6.78
These Results also show that the Weight of The School Bag is Heavier on Monday than on Thursday, which the attached graphs/charts also show.
Conclusion: The results received from the my questionnaire prove my first two hypothesis which are:
- The Weight of the Bag will be Slightly Heavier as it is the start of the week, and students have a lot of work to turn in
- The Weight of the Bag will be Slightly Lighter as it is just before the end of the week.
From the Male Student Section, you can see through the mean and Standard Deviation that the weight is heavier on Monday then on Thursday, Which is also true for Female Students as well.
Another Thing worth noting was that the overall weight of Female Student Bags was slightly less than Male Students disproving my last hypothesis:
-
The Weight will also depend on the Miscellaneous Items the Student is carrying, so it is hard to determine which gender will have the Heavier bag but it should be about the same.
Evaluation: Overall, my Coursework went pretty well but there were many factors that needed to be addressed such as the inability of many students to complete my Questionnaire, which I’ll admit was very difficult and time-consuming. Another Problem was the limited age group which limited the results a lot, as younger student could have lighter/heavier bags. Another problem was that only 10 people were chosen from each form group, which could have increased as well, thus giving more reliable results. One more thing would be the Lack of Secondary Data available on this topic, which I could not find to include in my work