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# An experiment to determine the concentration of the Descaling solution, Methanoic Acid.

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Introduction

An experiment to determine the concentration of the Descaling solution, Methanoic Acid. The Problem Find the concentration of methanoic acid, using methanoic acid solution and titrating them. Apparatus Burette Volumetric Pipette Beakers Conical Flasks Volumetric Flasks Funnel Clamp Stand White Tile Method Measure out 25cm3 of Methanoic acid of known concentration for the titration using the volumetric pipette. Assemble apparatus (as shown in diagram) after collecting goggles and lab coat for safety. Move your apparatus to eve level (i.e. to a stool) and pour the Methanoic acid in till the meniscus rests on the 0 level exactly so that your results can be measured accurately from the same marker every time. Move the apparatus back onto the table, and measure 25cm3 of methanoic acid accurately with the volumetric pipette (ensuring that it is clean, washed with distilled water then the solution you are using) ...read more.

Middle

Keep the tap running until clear patches start to appear in the swirling solution in the flask then slow the tap down and let the Methanoic acid drip in one drop at a time, all the time mixing it in, until the solution goes completely colourless. This is the End Point and an equilibrium has been reached, as the solution is neutral. Make a final reading by moving the burette and stand back onto a stool and reading it at eye level, from the bottom of the meniscus. Record the result to 2 decimal places for accuracy. then did the same, 5 times for the Methanoic acid solution. Results Table Experiment No. Start Amount End Amount Overall Quantity of Methanoic acid required to neutralise:25 TRIAL ** 1 0.00 22.80 22.80 ACTUAL EXP. ...read more.

Conclusion

In the equation :- Where V is Volume, c is Concentration and n is number of moles. Let the Methanoic acid be solution A, and the Methanoic acid be solution B. To work out the concentration of A, cA, we need to know all the other factors which make up the formula. Number of Moles in Methanoic acid, nB: 22.62 cm3 = 22.62/1000 dm3 = 0.02262 dm3 No of Moles = Concentration x Volume (dm3) = 0.05 x 0.02262 = 0.011308 = 1.13 x 10-3 mol No of Moles of NaOH :- Ratio of Solutions according to balanced equation = Methanoic acid : NaOH = 2 : 1 Therefore number of moles in NaOH , nA, = 1.13 x 10-3 mol / 2 = 5.65 x 10-4 mol Now I have all the other parts of the main equation apart from cA so I can work out cA. ...read more.

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