Catalase activity in the liver

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     NAME: JOE TROIANO        FORM: 5B      CAND. NUMBER:

INTRODUCTION

  The overall aim of this experiment is to investigate catalase activity in the liver. I will be watching to see what happens to the speed of reaction when the temperature rises.  I will also be looking at when the catalase enzymes perform the reaction the quickest and when the catalase performing the reaction slowest (or maybe not at all). Before I took my preliminary experiment I decided to take my experiment at these temperatures 0°C, 10°C, 20°C, 30°C, 40°C, 50°C, 60°C, 70°C and 80°C. I will find out in my preliminary experiment whether to use a test tube or a boiling tube. I will use 1g of liver and 2ml of Hydrogen Peroxide per each test tube. I will heat the experiment using a Bunsen burner and a thermometer to tell me when it is at the temperature I want. I will repeat the experiment 3 times.

     But after my preliminary I decided to make some changes and here they are-

  1. Use a test tube instead of a boiling tube because a boiling tube is too big.
  2.  I will use a stock solution (this is crushed liver mixed with water) I will use this because it is evenly concentrated.
  3. I will use the temperatures 0°C, 10°C, 20°C, 30°C, 40°C, 50°C, 60°C and 70°C I will not use 80°C because by 70°C the enzymes have already disnatured so there is no point in doing 80°C.
  4. I will use 2ml of stock solution in each test tube and the amount of hydrogen peroxide will be 1ml.
  5. I will repeat the experiment 7 times because this gives me a more accurate average.
  6. I will use a water baths at the chosen temperatures to heat the experiment because it is a lot easier to keep it at the wanted temperature.

Now after these changes I know how to do this experiment.

WHAT FACTORS DO YOU NEED TO CONTROL OR VARY IN THIS EXPERIMENT? 

   This is the definition of a fair test that I will have to remember throughout this experiment-

     Only one factor is changed at a time while all other factors are kept, as they’re highest and best value.

  In this experiment I only need to vary one thing and this is the temperature of the stock solution. The way I will vary the temperature is by having eight water baths at my chosen temperature and once it reaches the right temperature I will perform the experiment straight away so it does not lose any heat. The temperature of each water bath will vary but separately the water bath will have the same temperature so they are controlled I will do this by setting each water bath at my wanted temperatures I will also be checking the water baths to see if they are at the right temperature by putting a thermometer in each water bath.

The things I have to control in this experiment are as follows-

 When the reaction is taking place for each experiment I will measure the height of froth from the top of the mixture level therefore each experiment will be measured from the same place in all of the test tubes. The concentration of the enzyme will be controlled by using a stock solution this is because the mixture of crushed liver and water then sieved will make the mixture contain almost an even amount of enzymes. The type of tubes I will be using will remain constant and they will be test tubes they will remain the same to keep a fair test (if you are measuring up a tube they will all have to be the same size to keep it fair). The amount of stock solution and hydrogen peroxide will also be a constant I will do this by for each test tube I will put 2ml of stock solution and after it is heated to my wanted temperature I will add 1ml of hydrogen peroxide in it. When taking the temperature of the stock solution to see if it has reached my wanted temperature, I will always take the temperature at the bottom of the test tube this keeps the experiment a fair test.

 The reaction that takes place in this experiment is

                                                                                 

 2H202                 2H20 + 02     

WHAT DO YOU PREDICT WILL HAPPEN?

   The way I will prove that the enzymes are the reason for oxygen to be given off (in the form of froth) in my experiment is by performing an all or nothing experiment. The way I will do this is by, firstly heat 2ml of stock solution in a test tube to 70°C; I will do this because I have learned that at this temperature the enzymes denature or die. So the enzymes in this part of the experiment will take no place in this part of the experiment. In the other test tube I will heat 2ml of stock solution to 40°C this is because I have found out at this temperature enzymes work the quickest. Then I will add 1ml of hydrogen peroxide to both of the test tubes and measure the length of foam that is released with a ruler I will also repeat this 7 times to make sure it is accurate. Overall for the all or nothing I predict that at 70°C the amount of oxygen (or froth) that will be released will be nothing. At 40°C I predict the froth will rise the highest up the test tube than all of the different temperatures.

  From my continuous experiment I predict that every 10°C you go up from 0°C to 40°C the rate of reaction will double but after 40°C for example at 50°C the active sites would of started to denature so the rate of reaction would of started to slow down. By 60°C some of the enzymes will not be able to perform the reactions but by 70°C the enzymes would of stopped reacting with the hydrogen peroxide. This is the Q10 theory and if this happens the graph will look like the graph on the next page.

 USE SCIENTIFICF UNDERSTANDING TO EXPLAIN YOUR PREDICTION.     

   From my research and my preliminary work I have learned that hydrogen peroxide is a waste product of some reactions within the body. But it is able for the liver to detoxify the compound using the enzyme catalase. What the enzyme catalase does in this experiment is to convert hazardous hydrogen peroxide into harmless oxygen and water. This is what takes place in the reaction –

           2H202                         2H20 + 02

     The enzyme catalase in this experiment helps to speed up the rate of reaction and break down substances without itself undergoing any chemical change. An enzyme is composed of polymers of amino acids I have also found each enzyme is specific to one job so it can’t be used in other reactions. After looking at my preliminary work and research I have found out that enzyme catalase is quite a powerful catalyst so it has to be used in small amounts. I have also found out that enzymes can be used again and again. From my preliminary work, prediction and research I can see that enzyme catalase is effected by temperature, PH, enzyme concentrations and substrate concentrations.

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   In my prediction I said that from 0°C every 10°C you go up to 40°C the temperature will double this is because as enzymes are heated they start to accelerate the rate of reaction (but they are more unstable). The reason for why the rate of reaction increases as the temperature increases is because in order to react, the particles in the substance must collide with each other. Heat gives them more energy to move around and so it increases the chance of reaction. This is what it looks like-

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