Chemistry Coursework - How the concentration effects the rate of reaction between sodium thiosulphate and hydrochloric acid.

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+Chemistry Coursework-How the concentration effects the rate of reaction between sodium thiosulphate and hydrochloric acid

By Jess McFarlane 11WM

Introduction

        Sodium thiosulphate and hydrochloric acid are two colourless solutions that gradually react together to form a cloudy yellow precipitate of sulphur when they are mixed. I am looking to record the rate of reaction, which is measured by dividing 1 by the time taken for the reaction to occur, (1/time taken). I have chosen to vary the concentration because it is more practical to investigate, as it would take longer to prepare if I varied the temperature of the reactants and also it is much more difficult to obtain a desired temperature of a reactant, which will produce less accurate results. The chemical equation for this experiment should look like this:

HCl + sodium thiosulphate                  sodium chloride + sulphur dioxide + sulphur + water.

2HCl (aq) + Na2S2O3 (aq)                     2NaCl (aq) + SO2 (g) + S (s) + H2O (l)

My aim is to do this experiment but vary the concentration of the sodium thiosulphate so that it will affect the rate of reaction and I can then record and see why this reaction occurs.

There are a few factors that could affect my experiment and the rate of reaction and so they need to be kept constant in order for my experiment to work. The collision theory states that reacting particles factors, which will affect the rate of a reaction. And the main two in this experiment the temperature, and the concentration of the solution.

Prediction

        First of all I predict that as the concentration of the sodium thiosulphate increases, the rate of reaction will be faster and therefore make the X on the card under the conical flask disappear quicker. This is due to the effect of the collision theory. As the concentration is higher this means that there are mare sodium thiosulphate molecules to react with HCl molecules. As the HCl will be kept as a constant there will always be the same amount of molecules but as the sodium thiosulphate is being watered down this means that there will be less molecules for more successful collisions. What happens is the molecules in the two solutions mixed will be “free” as a figure of speech until they collide with another molecule that it can react with and the end result should be a yellow precipitation to be formed. A successful collision is one in which there is enough energy for the activation energy to be achieved so that the reactant particles react together. The activation energy is the amount of energy needed for the bonds to break.

As shown above, in the lower concentrated solution diagram there are fewer reactant particles of sodium thiosulphate, due to the fact that the solution has been watered down by the dilute water, therefore there will be less successful collisions, as fewer particles will be reacting in a the same period of time. This means that the rate of reaction will actually be slower than the high concentration solution. And so therefore I would expect that as the concentration of the solution is doubled the rate of reaction would also double, which would seemingly show that the two factors are proportional to each other and if this would turn out to be true, if the concentration is halved the rate of reaction will also halve.

In the higher concentrated solution diagram though, there are obviously more reactant particles of sodium thiosulphate and so there will be more successful collisions leading to a faster reaction rate. This is only an example of what the solutions should look like but this may be incorrect due to experimental error. There will also be a variation of concentrated solutions.

I personally would make a prediction that the activation energy needed to break the bonds of the atoms should not change in this experiment because the same amount energy will be required to break the bonds. This is due to the fact that each particle has the same amount of energy, the only reason the reaction is faster is because there are more particles, so there are more useful collisions. This means activation energy will not have an effect on this experiment, since there is not any form of a catalyst present to lower the activation energy (a catalyst being a substance which increases the speed of a reaction without being changed or used up in the reaction). The diagram below helps to understand this concept slightly more:

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I would expect that the reaction that occurs will be likely exothermic, which means it will give out heat. I predict this because as a precipitate is being formed I think that the amount of energy needed to break the bonds will be less than the energy needed to make the new bonds.

Apparatus

  1. Sodium thiosulphate solution- will be mixed with the hydrochloric acid
  2. 2M Hydrochloric acid (dilute)- will be mixed with the sodium thiosulphate and on separate occasions for purposes of the experiment it ...

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This is a detailed experiment, however the author repeats themselves many times throughout. It is not set out very well and has no diagrams or graphs to view. The science is sound, but very basic Overall, this piece of work is 2 stars out of 5