Determination of the relative atomic mass of lithium

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Determination of the relative atomic mass of lithium

Results – method 1

Mass of lithium used  - 0.10g

Volume of hydrogen evolved – 188.00cm

Results – method 2

Average volume of Hydrochloric Acid used = 34.98 + 34.94 / 2

                                                   = 34.96 cm

Calculations – method 1

2Li + 2H2O           2LiOH +H2

                             2 moles                                            1 mole

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1 mole of gas occupies 24000cm³ at RTP

Volume of H2 gas evolved = 188cm³

188 / 24000 = 0.0078 moles

0.0078   2 = 0.016 moles (2sf)

Ar = 0.10 / 0.016 = 6.383 (3dp)

Calculations – method 2

LiOH + HCl               LiCl + H2O

     1 mole                    1 mole

0.10   34.96 / 1000 = 0.003496 moles

= 0.0035 (2sf) moles in 25cm³of LiOH

0.003496 x 4 = 0.013984 moles

= 0.014 (2sf) moles in 100cm³ of LiOH

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