Does changing the concentration of Hydrogen Peroxide
have an affect on the rate of reaction.
Skill Area P: Planning
To investigate the rate of this reaction, I need to measure something that changes during the reaction and have chosen a property that is easy to detect being the volume of gas that is given off. I will measure it at fixed time intervals and keep all the other variables constant.
There are several factors that can influence the rate of a chemical reaction. In general, a factor that increases the number of collisions between particles will increase the reaction rate and a factor that decreases the number of collisions between particles will decrease the chemical reaction rate.
These are the five main factors that can have an affect on the rate of reaction.
These are:-
* Temperature
* Surface area
* Catalysts
* Concentration
* Pressure
I am going to look only at the four variables that we are able to control in this experiment which are the first four shown on the list.
Temperature
Usually, an increase in temperature is accompanied by an increase in the reaction rate. Temperature is a measure of the kinetic energy of a system, so higher temperature implies higher average kinetic energy of molecules and more collisions per unit time. A general rule of thumb for most (not all) chemical reactions is that the rate at which the reaction proceeds will approximately double for each 10°C increase in temperature. Once the temperature reaches a certain point, some of the chemical species may be altered (e.g., denaturing of proteins) and the chemical reaction will slow or stop.
Surface Area
The surface of a solid, in this case a potato, means the amount of surface that is exposed to the outside. If you cut up an object into smaller pieces, the surface area gets larger and so the reaction is made faster.
Presence of Catalysts
Catalysts (e.g. enzymes) lower the activation energy of a chemical reaction and increase the rate of a chemical reaction without being consumed in the process. Catalysts work by increasing the frequency of collisions between reactants, altering the orientation of reactants so that more collisions are effective. The presence of a catalyst helps a reaction to proceed more quickly to its equilibrium.
Concentration
In any reaction involving solutions, a concentrated solution always reacts faster than a diluted one. 'Concentrated' means the solution has a lot of solute dissolved in a particular volume. In other words the more Hydrogen Peroxide that is added to the potato the faster the reaction will become.
In my experiment I have chosen to use the factor of concentration for my variable. I predict that as I increase the volume of Hydrogen Peroxide the amount of oxygen produced will increase. My prediction is based on the idea of Collision Theory. This theory states that:
Chemical reactions occur when particles of the reactants collide. They must collide with a certain minimum energy, called the activation energy.
This is essentially a process that occurs in every reaction. To react two reactants have to collide with one another, what's more the molecules have to collide with enough force - the activation energy, otherwise they will just bounce off each other harmlessly. The activation energy is needed to break the bonds in the molecules and get the reaction started. The diagram below shows how increasing the concentration of the Hydrogen Peroxide raises the amount of oxygen produced.
Source: 'Chemistry' Nelson Science - John Holman (1995)
Prior to the main experiment I carried out a preliminary test to determine which way I would do the experiment to maximise fairness, safety, accuracy, and simplicity. The variable that I was changing was concentration but instead of using a cork borer to obtain the right length and diameter potato I cut the potato into squares 1cm × 0.5cm × 0.5cm. I chose to time how long it would take to obtain 10 bubbles from the reaction because I thought this to be a sensible number and it would be easier to plot when I was to draw up the graph. The results I got from this initial experiment are shown below.
have an affect on the rate of reaction.
Skill Area P: Planning
To investigate the rate of this reaction, I need to measure something that changes during the reaction and have chosen a property that is easy to detect being the volume of gas that is given off. I will measure it at fixed time intervals and keep all the other variables constant.
There are several factors that can influence the rate of a chemical reaction. In general, a factor that increases the number of collisions between particles will increase the reaction rate and a factor that decreases the number of collisions between particles will decrease the chemical reaction rate.
These are the five main factors that can have an affect on the rate of reaction.
These are:-
* Temperature
* Surface area
* Catalysts
* Concentration
* Pressure
I am going to look only at the four variables that we are able to control in this experiment which are the first four shown on the list.
Temperature
Usually, an increase in temperature is accompanied by an increase in the reaction rate. Temperature is a measure of the kinetic energy of a system, so higher temperature implies higher average kinetic energy of molecules and more collisions per unit time. A general rule of thumb for most (not all) chemical reactions is that the rate at which the reaction proceeds will approximately double for each 10°C increase in temperature. Once the temperature reaches a certain point, some of the chemical species may be altered (e.g., denaturing of proteins) and the chemical reaction will slow or stop.
Surface Area
The surface of a solid, in this case a potato, means the amount of surface that is exposed to the outside. If you cut up an object into smaller pieces, the surface area gets larger and so the reaction is made faster.
Presence of Catalysts
Catalysts (e.g. enzymes) lower the activation energy of a chemical reaction and increase the rate of a chemical reaction without being consumed in the process. Catalysts work by increasing the frequency of collisions between reactants, altering the orientation of reactants so that more collisions are effective. The presence of a catalyst helps a reaction to proceed more quickly to its equilibrium.
Concentration
In any reaction involving solutions, a concentrated solution always reacts faster than a diluted one. 'Concentrated' means the solution has a lot of solute dissolved in a particular volume. In other words the more Hydrogen Peroxide that is added to the potato the faster the reaction will become.
In my experiment I have chosen to use the factor of concentration for my variable. I predict that as I increase the volume of Hydrogen Peroxide the amount of oxygen produced will increase. My prediction is based on the idea of Collision Theory. This theory states that:
Chemical reactions occur when particles of the reactants collide. They must collide with a certain minimum energy, called the activation energy.
This is essentially a process that occurs in every reaction. To react two reactants have to collide with one another, what's more the molecules have to collide with enough force - the activation energy, otherwise they will just bounce off each other harmlessly. The activation energy is needed to break the bonds in the molecules and get the reaction started. The diagram below shows how increasing the concentration of the Hydrogen Peroxide raises the amount of oxygen produced.
Source: 'Chemistry' Nelson Science - John Holman (1995)
Prior to the main experiment I carried out a preliminary test to determine which way I would do the experiment to maximise fairness, safety, accuracy, and simplicity. The variable that I was changing was concentration but instead of using a cork borer to obtain the right length and diameter potato I cut the potato into squares 1cm × 0.5cm × 0.5cm. I chose to time how long it would take to obtain 10 bubbles from the reaction because I thought this to be a sensible number and it would be easier to plot when I was to draw up the graph. The results I got from this initial experiment are shown below.