Electrolysis Using Copper Sulphate And Copper Electrodes

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Susanna Liniker, Candidate Number 0069

Electrolysis Using Copper Sulphate And Copper Electrodes

Introduction

In this experiment copper sulphate will be electrolysed using copper electrodes to find the loss of mass of the anode. The copper anode will be weighed before and after the experiment. Each time the experiment is done the time will be increased by 2.5 minutes until 25 minutes is reached. So the first experiment will last 2.5 minutes and the second 5 minutes. The results will be plotted on a graph of loss of mass against time.

Aim 

To find the loss of mass of anode when electrolysing copper electrodes using copper sulphate solution for different times.

Background Information

Electrolysis is used to purify copper. Ken Gadd and Steve Gurr state that electrolysis is “the process of decomposition”. For electrolysis to occur the circuit shown below must be set up:

The battery is used to supply the energy for the free electrons inside the wires to move. The wires are in turn used to connect the two electrodes (conducting rods) to the battery. The electrodes are then placed inside the electrolyte (the substance that ions move in), which in this experiment is copper (II) sulphate solution. In industry the impure copper would be used as the anode and the pure copper used as the cathode.

When the electrodes are connected to the battery the anode should be positively charged and the cathode negatively charged. Opposite charges attract so the positively charged ions would move towards the cathode and negatively charged ions would move towards the anode. Gallagher and Ingram say, “Cations go to the cathode. Anions go to the anode”, therefore, metals such as copper that are positively charged are cations.

Hill and Holman, who are talking about the electrolysis of sodium chloride, say, “when Na+ ions reach the cathode they combine with negative electrons from the battery forming neutral sodium atoms”. This can also be applied to electrolysis using copper sulphate and copper electrodes as copper ions, which are positively charged and therefore cations, from the anode will travel through the copper sulphate and be attracted towards the cathode. There they will combine with negative electrons forming neutral copper atoms. Therefore, at the cathode there will be a build up of copper and at the anode there is a loss of copper.

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To calculate how much copper will deposit on the cathode, first of all the electrical charge must be calculated by the formula: Q = I x t. The time would be varied in the experiment and the current kept constant so for each time the charge can be calculated. Gallagher and Ingram say, “1 mole of electrons has a charge of 96500 coulombs” therefore, 1/96500 multiplied by the number of coulombs would show how many moles of electrons are used. After writing an equation for the reaction at the cathode, which ...

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