In this experiment I am finding out how much sulphuric acid is present in sodium carbonate solution.

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AS Chemistry Coursework

Aim: In this experiment I am finding out how much sulphuric acid is present in sodium carbonate solution.

How I will find the accurate concentration of sulphuric acid

I am to find the accurate concentration of sulphuric acid ranging between 0.05 and 0.15-mol dm-3, I am provided with solid, anhydrous sodium carbonate, and range of indicators. The indicator which I will be using in my experiment is methyl orange, because it is used in most titrations, and it changes colour as a mid strength acid. It has sharper end point then universal indicators. The pH of methyl orange is 3.1 - 4.4.

 

This is the chemical balanced equation that will take place, during my experiment.

Equation:  H2SO4 (aq) + Na2COaq) → Na2SO4 (aq) + H2O (l) + CO2 (g)

 

From looking at the equation we can see that one mole of aqueous sulphuric acid reacts with one mole of sodium carbonate. (These are the reactants). This forms the (products) which is one mole of aqueous   sodium carbonate, one mole of water and one mole of carbon dioxide. The balanced chemical equation is in a 1:1 ratio.

Choosing the concentration of sodium carbonate solution

The concentration of sodium carbonate which I will choose will be 0.1 mol dm-3, I have chosen this concentration because it is halfway between 0.05 and 0.15 moldm-3   of sulphuric acid concentration, I added, 0.05 and 0.15 and found out the average concentration which I could use was 0.1 mol dm-3, this has therefore given me a basic idea that my sodium carbonate solution should be ranging near that concentration. I will be making a 250cm3 solution.

Working out the mass of sodium carbonate used

1000cm3 is equivalent to 1dm3. I need to convert 250cm to dm3. This is done by dividing 250cm by a 1000 (250          1000), which equals to 0.25dm3. Now I have worked out the volume of anhydrous sodium carbonate needed is 0.25dm3.

Working out the number of moles of sodium carbonate needed

 

We can use the formula n=cv to work out the number of moles of sodium carbonate needed.

N: Represents Number of moles (mol)

C: Represents concentration (mol dm-3)

V: Represents Volume (dm3)

I need to rearrange the equation to work out the number of moles of sodium carbonate needed.

This is the rearranged equation

Moles = concentration (mol-1 dm-3) x volume (dm3)

Therefore,

0.1 x    0.25 = 0.025 mol

0.025 mol of sodium carbonate is needed.

Working out Mass of sodium carbonate needed

I can work out the mass of sodium carbonate needed by using the equation:

Mass

________       = Amount in Moles

Molar Mass

I already know that 0.025 mols of sodium carbonate are needed. I need to work out the unknown, which is the Relative formula mass of sodium carbonate.

Firstly I know that the formula of sodium carbonate is:  Na2CO3

Finding out the relative mass of each individual element, and then adding each of the elements relative mass together to give an overall molecular mass can work out the relative molecular mass.

The mass of Sodium (Na) is: 23

There are 2 sodium atoms; therefore the mass of sodium (which is 11) is multiplied by 2 to give 22 (23 x 2 = 46)

The mass of Carbon (C) is 12

The mass of Oxygen (O) is: 16, however there is 3 atoms of Oxygen therefore; we need to multiply the mass of Oxygen (which is 16) by 3 to give 48.

The masses of all the elements, are added together

          Na2                C             O3

          46        + 12     + 48    = 106

Therefore the relative molecular mass of sodium carbonate is 106 RMM

Now that I know 0.025mols of sodium carbonate is needed, and the relative molecular mass of sodium carbonate is 106. I can apply this to the equation.

Mass

________       = Amount in Moles

Molar Mass

 I will need to rearrange the equation

Therefore:   Number of moles (mol) x   Molar Mass = Mass

                         0.025                               x      106           = 2.65g

2.65g of anhydrous sodium carbonate crystals are needed.

                       

Apparatus used

1         Graduated Conical Flask

2        Volumetric Flask (250cm3) -Used to prepare standard solutions of solute

3        Burette

4        Pipette- to deliver accurate volume of sodium carbonate solution into the conical flask

5        Electronic Weighing scale- to weigh anhydrous sodium carbonate

6        Beaker (Optional)

7        White tile

8        Pipette filler to adjust the volume of sodium carbonate solution being entered in the conical flask and to make an accurate measurement of sodium carbonate solution.

9        Wash bottle (Distilled water)- To make sodium carbonate solution, and wash of any impurities, in the apparatus being used.

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10        Retort stand

11        Boss and clamp

12. Small filter

Making the sodium carbonate solution

1.        Use a weighing bottle/boat weighs out accurately (using an electrical weighing scale), about 2.65 g of anhydrous sodium carbonate. Record the exact mass of anhydrous sodium carbonate transferred, in a suitable table; calculate the weight of the weighing boat.

2. Before using any apparatus make sure that all apparatus are clean, there is no impurities left over, make sure to wash apparatus with distilled water. This is done because impurities, or any precipitates left over can have an effect on the results ...

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