Investigating the Water Potential of the potato cells.

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Shama Lalji

 BIOLOGY COURSEWORK

Investigating the Water Potential of the potato cells.

INTRODUCTION:

In my experiment I will be looking at the water potential of potatoes. The potato tuber is made up of plant cells, each of which is surrounded by a cell wall that is permeable and a cell membrane that is selectively permeable. This is important as water can move in and out of this permeable membrane.

The tendency of water molecules to move from one place to another is called water potential. The symbol for water potential is the Greek letter psi Ψ. This process is called osmosis; it can be defined as the movement of water molecules from a region of higher water potential to a region of lower water potential through a partially permeable membrane.

Pure water has a water potential of zero, the addition of a solute lowers the water potential so all water potential values are less then zero therefore minus. Water tends to move from a less concentrated to a more concentrated solution, i.e. from areas of low negative potential to areas of high negative potential. Equilibrium is when there is the same amount of water molecules in both solutions, which therefore stops the net movement of water molecules.

Since solutes make water potential lower, the more solute the more negative the water potential becomes. The amount that the solute molecules lower the water potential of a solution is called solute potential. The symbol for solute potential is Ψs.

EQUIPMENT:

  • 6 boiling tubes for each molarity level         
  • Labels for test tubes
  • Test tube rack
  • Scalpels for cutting potato samples
  • Ruler
  • Cork borer
  • Electronic Weighing scales
  • 2 Beakers for measuring solutions
  • Filter paper for drying potato samples
  • 2 Syringes
  • Distilled water
  • 1.0 molarity sucrose solution
  • Potato
  • Potato borer
  • White tile
  • Stop Watch

PREDICTION:

In my potato experiment I will make different concentrations of solution and place the potato tubes in them observing and measuring the mass gain or loss.

My prediction is that in a solution of high concentration the potato will lose water and mass and gain water and mass in solutions of lower concentration this is due to water tends to move from a less concentrated to a more concentrated solution, i.e. from areas of low negative potential to areas of high negative potential. Also if the potato’s mass and volume stays the same the water potential is the same so therefore the water potential of the potato is the same as the solution where it neither gains or losses mass. Therefore I predict that at around the 0.6-molarity solution there will be not much change so the potato will be in equilibrium. Therefore solute potential according to Fig 1:b will be around –1800kPa.

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VARIABLES:

In this experiment there should only be two changing variables:

1: Different molarities of sugar solution.

2: Changing mass of the potato samples.

To keep these two variables the only variables in the experiment I must:

1: Keep the potato samples the same length (4cm) and diameter. This is because if one potato sample is 3cm long and one is 5cm long then the 5cm long sample will have a larger surface area.

2: Use the same potato. This is because many factors due to the potato may affect the experiment. For example the age, ...

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