Investigation to discover the affect of varying concentrations on the rate of reaction of CaCo3.

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Omar Khaliq 11B

Science

Miss.Cole

Investigation to discover the affect of varying concentrations on the rate of reaction of CaCo3

Hypothesis:

I predict that the greater the concentration of hydrochloric acid (HCL) is the faster the limestone chips shall dissolve in the solution.  In a greater concentration of hydrochloric acid (HCL) there are more particles and therefore more collisions per second occur in, turn this results in an increase in the rate of reaction.  As there are more particles for the reactant to react with.  A for m of energy given off this reaction is heat.  During the reaction the amount of Carbon Dioxide (CO2) allows us to relate how volatile the substance is.  For instance the more Carbon Dioxide (CO2) bubble produced the more volatile the substance is as Carbon Dioxide (CO2) is produced from a reaction.

I predict that as the concentration increases, the average speed of particles colliding increases.  At higher concentration there are more particles allowing, there to be more collisions per second and this results in an increase in the rate of reaction.  A reaction will only occur if the colliding particles possess more than a certain minimum amount of energy. 

This minimum energy for a reaction to occur is known as the activation energy (A.E).  The activation energy enables chemical bonds to stretch and break the rearrangements of the atom, ions and electrons to occur as the reaction proceeds.

From the Collision Theory it is stated that in a reaction between two gaseous substances A&B a molecule of A must collide with B for the reaction to proceed but in a concentrated solution there will be a higher percent of reactants which will have no more energy. Not all collisions cause a reaction, only the ones which reach the activation energy of the reaction. This is why I predict that the rate of reaction will increase as the concentration of a solution increases.

 As a result of the concentration rising I predict that the particles in the limestone chips receive more energy and start colliding with each other to increase the rate of reaction, the rate simply depends on how hard and often the reacting particles collide with each other inside the boiling tube.  The energy (gas) given off increases as stated before, therefore I predict that the reaction using the highest concentration (1.5m) will produce the highest amount of gas in the shortest time. I will measure the gas by reading it off from the flask.

The acid does not dissolve the limestone chips it reacts with them as two separate reactants; the shape of the chips stays the same but after the experiment they cannot be used again because the acid would have used all the potential reactant energy to make the gas substance.  This is therefore an exothermic reaction as it releases heat due to the reaction. 

For the molarities between 0.25 and 1.00 we shall measure the amount of carbon dioxide produced by the experiment from the calibrated collecting tube every 15 seconds until we reached 120 seconds which is a total of 8 checkpoints. For the remaining molarities we shall measure the amount of carbon dioxide produce for a total of 80 seconds at 10 second intervals. These observations will also enable me to see if the reaction is slowing down or speeding up at all.  I predict that the more concentrated the solution is, the reaction will speed up producing more gas in a shorter space of time. 

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Method:

First of all I am going to test the rate of reactivity of the calcium carbonate (limestone chips) at room temperature =27°c, this is because it was a heated room.

I measured 6 0.50grams of limestone chips and added individual 0.50 grams into separate boiling tubes with 10ml of Hydrochloric acid which was measure using a measuring cylinder.  I then added the acid into the boiling tube with the limestone chips and started the stop clock straight away. For the molarities between 0.25 and 1.00 molars we measure the amount of carbon dioxide produce by the ...

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