# My aim of this experiment is to find out the concentration of NaOH by titration with standard o.1dm3 Hcl solution.

My aim of this experiment is to find out the concentration of NaOH by titration with standard o.1dm3 Hcl solution.

• The Set up equipment was  Set up
• Add 25.00 ml of orange juice to a 125 ml Erlenmeyer flask.
• The burette was rinse with a small volume of the Hcl solution and then fills it.
• The Titrate has been continued until the endpoint was reached by added Hcl solution and the colour was persists longer than 20 seconds.)
• Record the final volume of NaOH solution
• The titration repeated until the three measurements that agreed to within 0.1 ml.

Calculation:

NaOH +Hcl        Nacl +OH +H2o

Using the equation 1 mol of NaOH react with 1 mol of Hcl

The mean titre = 23.90 +23.90   =

47.8 ÷2   = 23.9 cm3

= 23.9 cm3 to dm3

23.9 ÷   1000 =    0.0239dm3

First working out the number of moles from the burette

Moles = c   × vdm3

C = 0.1, v = 0.0239

Moles = 0.1 ×   0.0239 =     2.39 ×10-3

Step 2 working out   the Concentration of NaOH in the flask

C = mole ÷ v dm3

V = 25 cm3   ÷   1ooo =0.025dm3

C = 2.39 ×10-3 ÷ 0.025   =   0.0956 moledm3

The strongest and weakens of the experiment.

During the experiment there are some of the human error that occurred , which include reading ...