My aim of this experiment is to find out the concentration of NaOH by titration with standard o.1dm3 Hcl solution.

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My aim of this experiment is to find out the concentration of NaOH by titration with standard o.1dm3 Hcl solution.

  • The Set up equipment was  Set up
  • Add 25.00 ml of orange juice to a 125 ml Erlenmeyer flask.
  • The burette was rinse with a small volume of the Hcl solution and then fills it.
  • The Titrate has been continued until the endpoint was reached by added Hcl solution and the colour was persists longer than 20 seconds.)
  • Record the final volume of NaOH solution
  • The titration repeated until the three measurements that agreed to within 0.1 ml.

Calculation:

NaOH +Hcl        Nacl +OH +H2o

Using the equation 1 mol of NaOH react with 1 mol of Hcl

The mean titre = 23.90 +23.90   =  

47.8 ÷2   = 23.9 cm3

= 23.9 cm3 to dm3  

23.9 ÷   1000 =    0.0239dm3

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First working out the number of moles from the burette

Moles = c   × vdm3

C = 0.1, v = 0.0239

Moles = 0.1 ×   0.0239 =     2.39 ×10-3

Step 2 working out   the Concentration of NaOH in the flask

  C = mole ÷ v dm3

V = 25 cm3   ÷   1ooo =0.025dm3

C = 2.39 ×10-3 ÷ 0.025   =   0.0956 moledm3

The strongest and weakens of the experiment.

During the experiment there are some of the human error that occurred , which include reading ...

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