Sodium Thiosulphate + Hydrochloric Acid Coursework

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Sodium Thiosulphate + Hydrochloric Acid Coursework

Plan

Aim

I must produce a piece of coursework investigating the rates of reaction when Sodium Thiosulphate + Hydrochloric Acid are mixed.

The reaction that will be used is:

      Na    S    O       +    2CHl                                 2Na Cl  +    S     +   SO      +   H  O  

 

    Sodium      +     Hydrochloric                      Sodium    +  Sulphur  +   Sulphur   +   Water          Thioslphte                   Acid                      Chloride                           Dioxide

Variables

Other variables, which may affect the outcome of this experiment, if not kept constant, are as follows:

  • Temperature of liquids. I believe that the hotter the temperature, the faster the rate of reaction. This is because when a substance is heated up, each particle has more energy, resulting in more collisions between the free moving particles in a liquid, causing more particles to react, therefore increasing the overall rate of reaction. The second effect this has is that the particles collide with more force, increasing the chance of the particles reacting. I will keep this variable constant so that it does not affect the results by avoiding heating the sodium thiosulphate in any way, and so it will stay at room temperature.
  • Human Error/People. This experiment relays on people and their eye sight, because to determine how long the reaction takes a cross is put under the container and when it isn’t disappears the timer is stopped and the time is taken down. People have different eyesight’s and reaction times that can change the out comes.
  • Container. Although this does not affect the rate of reaction, in that it doesn't affect the chemical reaction itself, but what this variable does affect is our measurement of how long the reaction has taken to complete. I will be judging the time taken for the reaction to finish as the time it takes for the reacted mixture of sodium thiosulphate to go completely cloudy so that I cannot see a cross drawn underneath the flask. If the flask is wider then the cloudiness will appear less concentrated, because it will be spread across the larger area of the bottom of the conical flask, and so it will take longer for the cross to disappear, and the results will increase. I will keep this variable constant by using the same conical flask for each experiment.
  • Cross. The material I use draw the cross underneath the conical flask, which I use in determining when the reaction has finished, could affect how easily the cross is seen. This in turn could affect the results because if the cross is seen more easily, if it was drawn with a thick marker, our measurement of how long the reaction took to complete would be longer and so the rate of reaction would seem slower. Equally, if the cross was hard to see, then it would disappear more quickly and the rate of reaction would seem quicker. I will keep this constant by using the computer to design crosses which are the same size and thickness.
  • Concentration of acid. The more concentrated the hydrochloric acid, the faster the reaction will be, because there will be more particles in the same volume.
  • Stirring/ mixing. If I shake the conical flask while it is reacting, then the reaction may speed up and therefore the rate of reaction would be quicker. Likewise, if I stir it then it will increase the rate of reaction, because there will be a greater chance of the particles colliding with other particles which they can react with because the two types of particles will be more mixed together and also. I will prevent this from affecting the results by not stirring or shaking the mixture in any way.
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Prediction

        The concentration will increase the rate of reaction because if the concentration is higher, then there will be more molecules of Hydrochloric Acid in a given volume, and so it is reasonable to say that it greatly increases the chances of one of those molecules colliding with the hydrochloric acid molecules. This means that more of the molecules will be colliding and reacting within a given time, and so the rate of the reaction has speeded up. However, I do not have enough information on the subject to be able to make a quantitative prediction at this time.

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