Synthesis of Iron (II) Sulphate FeSO4

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Anglo-Chinese School (Independent)

Year 3IP Chemistry Coursework         Tong Viet Anh (29)

        3.18 Nathan

                

2008 YEAR 3 IP

CHEMISTRY PROJECT

Synthesis of Iron (II) Sulphate FeSO4

Friday, 18th July 2008

Tong Viet Anh

3.18 Nathan

A. Aim

To produce a pure and dry sample of Iron (II) Sulphate FeSO4 crystal

B. Apparatus & Materials

Apparatus:                                                Chemical:

100ml Beaker (1)                                        Distilled water        

Glass rod (1)                                                Sulphuric acid 1 mol/dm3 (H2SO4)

Spatula (1)                                                Iron filings (Fe)

Filter paper (3)

Filter funnel (1)

Evaporating dish (1)

Bunsen burner (1)

Tripods stand (1)

Wire gauze (1)

Lighter (1)

Cloth (1)

IR light (1)

Plastic bag (1)

Goggles

C. Method

(Reactions of acid and metals)

  1. Wash up the beaker, evaporating dish, funnel and glass rod so as to remove as much unwanted particles as possible and get the purest crystals.
  2. Measure 40 cm3 of dilute Sulphuric acid (H2SO4) and pour it into the beaker.
  3. Warm the acid to speed up reaction.
  4. Add Iron fillings (Fe) one spatula at a time, stirring until no more or little Iron fillings dissolves.
  5. Remove the excess of Iron (Fe) by filtering the mixture into an evaporating dish
  6. The light green solution in the evaporating dish is dilute Iron (II) Sulphate (FeSO4)
  7. Heat gently by the Bunsen burner and evaporate filtrate (until only one-third left).
  8. Let the solution cool down naturally after a few days
  9. Filter to obtain crystals and wash with distilled water
  10. Press crystals lightly between pieces of filter paper and air-dry or use IR light for 1-2 minute.
  11. Take to crystals out and put in the sealed plastic bag.
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D. Results

Some shiny light-green crystals of Iron (II) Sulphate (FeSO4) are obtained along with some small brown particles and dust. Total weight of crystals of Iron (II) Sulphate (FeSO4) is 4.3 gram

The percentage yield of the salt:

The number of mol of Sulphuric acid (H2SO4) used:

40ml x 1mol/dm3 = 0.040dm3 x 1mol/dm3 = 0.040 mol

The reacting equation can be represented as

Fe + H2SO4  FeSO4 + H2

  • From the equation, 1 mol of Sulphuric acid reacts totally with excess Iron fillings (Fe) to form 1 mol of Iron (II) Sulphate (FeSO4)
  • Therefore, the expected amount of Iron ...

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