The Molecular Formula of Succinic Acid.

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The Molecular Formula of Succinic Acid

Introduction:

I have been provided with a sample of anhydrous succinic acid and my task is to determine via titration its true molecular formula where ‘n’ is a whole number between 1 and 4 to be found.

HOOC(CH2)NCOOH

The acid is a white crystalline solid and is very soluble in water. Succinic acid is also diprotic (dibasic) and in the same way as sulphuric acid a solution of succinic acid may be completely neutralised by sodium hydroxide solution. If succinic acid is represented as ‘H2A’ then the equation for full neutralisation is:

H2A + 2NaOH                   Na2A + 2H2O

(Phenolphthalein will be a suitable indicator)

Appreciation of scale:

Having been given a 0.1M solution of sodium hydroxide and told that succinic acid is dibasic, it then follows that a 0.05M solution of succinic would be most suitable due to the two to one ratio. As I don’t know the value of ‘n’ yet, only that its between 1 and 4, if I’m to work out the amount of acid required to make a 0.05M solution then I am going to have to use a hypothetical value for ‘n’. For this I have chosen ‘n=3’ as it is a middle or average value (neither the maximum or the minimum), this then giving succinic acid a molecular formula mass of 132g.

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To get a 0.05M succinic acid solution in 250cm3 will take how many grams of solid acid if ‘n=3’ and the molecular mass is 132g ?

            132g  in  1dm3  =  1M

             13.2g  in 1dm3 =  0.1M

               6.6g  in 1dm3 =  0.05M  

           1.65g  in 250cm3  =  0.05M

Therefore if ‘n=3’ its going to take 1.65g of succinic acid in 250cm3 to make a 0.05M solution, which is what is needed for the titration.

Preparation of Acid Solution:

To make a 0.05M solution once we know how much ...

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