Titration experiment - write up

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To analyse a solution of dilute sulphuric acid and calculate the concentration of acid it contains

Aim:

To determine the precise concentration of sulphuric acid solution, using a solution of accurately known strength, called a ‘standard solution’.

Introduction:

A titration is a laboratory technique used in chemical analysis. A solution containing an unknown quantity of a known substance is placed in a conical flask, and a solution of known strength is then added from a burette. 1 The addition of this solution continues until an end point of the titration is reached. This is signified by a colour change in an indicator (or some other visible effect) and at this point the titration is stopped. The equivalence point of the titration occurs when the two solutions have reacted exactly. An indicator is a substance that changes colour when the reaction is complete. In an acid – base titration, the indicator is one colour at one pH and a different colour at another pH. The indicator I will be using is methyl orange.

I will be using sodium carbonate, as it is suitable for use as a primary standard for titrations of strong acids. The strong acid I will be using is sulphuric acid, which is a  . It is soluble in  at all concentrations. It has many applications, and is one of the top products of the .2 A problem is that it produces acid rain. Acid rain is  or any other form of  that is unusually . It has harmful effects on plants, aquatic animals and buildings. Acid rain is mostly caused by human emissions of  and  compounds which react in the atmosphere to produce acids.3

 An acid is a substance which contains hydrogen and when dissolved in water furnishes hydrogen ions.

e.g.:  H2SO4 = 2H+ + SO4 2−

A base is a substance which will react with hydrogen ions to give a salt and water only. The base I will be using is sodium carbonate. The alkalis are substances which when dissolved in water furnish hydroxyl ions.

e.g.:  NaOH  = Na+ + OH

According to the Bronsted-Lowry theory the definition of an acid is a proton donor and a base is a proton acceptor.

Usefulness of titrations:

Titrations are important to understand how acids and bases react with each other, ways to understand detection of experimental error, and to experimentally calculate or figure out what a chemical or substance consists of or the properties it can contain. Titrations are a key tool in industry laboratories and for educational purposes. In addition a titration is not complicated, and is a fast and easy procedure, giving accurate results which are simple to reproduce. It is applied to biodiesel, used in the petrochemical and food industry.

Plan:

The amount of sodium carbonate required to make up 250 cm³ of the solution:

I plan to make up 250cm³ of sodium carbonate solution (Na2CO3); I have chosen to do so because the pipette I will be using has a volume of 25cm³, which means, with these volumes I can repeat my titration ten times, without the need of making up a new solution, this will save time.

The concentration of sulphuric acid (H2SO4) is between 0.05 and 0.15 mol dm -³, hence it is appropriate to choose the mid- point between these concentrations, which is 0.1 mol dm -³.

The balanced equation for the reaction:

1) Na2CO3 (aq)      +        H2SO4 (aq)      Na 2SO4 (aq)       +    H2O (aq)       +     CO2 (g)

2) Base                +     acid            →   salt                 +    water         +    gas

There is a 1:1 ratio of the compounds sodium carbonate and sulphuric acid, meaning one mole of Na2CO3 neutralises one mole of H2SO4.

Before making up my known 250cm³ of Na2CO3 solution, I will first need to find the amount of Na2CO3 needed to be dissolved in 250 cm³of distilled water for making a one molar solution. To do this I will find the molar mass of Na2CO3 then divide the molar mass (Mr) by 1000 to convert the units from cm³ to mol dm-³, I will then divide by 4 (because 1000/250 = 4) to get the exact amount of anhydrous sodium carbonate.

The Mr of Na2CO3:

Na =   23  x   2 = 46

C   =   2    x   1 = 12

O   =   6    x   3 = 48

46 + 12 + 48 = 106 grams of Na2CO3 = 1 mol of Na2CO3.

Hence, 106 grams dissolved in distilled water is the mass for a 1 litre solution which would give a concentration of 1 mol dm -³. As stated earlier I will use a 250 cm solution, therefore 1000cm would be an unwanted volume, as it is far too much. To decrease it to 250 cm I must divide my Mr by 4 and then by 10 to work out the mass needed for a 0.1 molar solution.

106/4 = 26.5 g

26.5 g/10 = 2.65 g

1000/4 = 250 cm of distilled water

Consequently, I will use 2.65g of Na2CO3, to give a 0.1 molar solution.

The indicator:

Acid-base indicators are generally weak acids, with a dissociation which can be represented as:

HIn (aq)         H+ (aq) + In- (aq)

The weak acid HIn and/or its conjugate base In-  is coloured. A change in pH causes a shift (in the equilibrium in the above equation) which causes a change in colour.

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A good indicator should show a dramatic colour change in order to make it easy to detect the end point of the titration. I will be using the recommended indicator methyl orange. In acid its colour is orange. In alkali its colour is pink.

Risk Assessment:

All substances must be handled with much care and precaution. During the experiment safety goggles will be worn at all times to protect the eyes, and protective clothing i.e. a lab coat will also be worn to protect the skin and clothing from any spillages.

Apparatus:

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