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Introduction

Name: Chan Lo Ho Class: 6A Class no.: 4 Date: KI4 To Determine the Activation Energy of the Reaction between Bromide ion and Bromate (V) ion in Acid Solution Objectives: By reacting Potassium Bromide and Potassium Bromate in the acid solution in varies temperature, we can then determine the Activation Energy of the reaction in different temperature through the equation:. Results: Experiment Temperature Time t/s ln 1/t Temperature K 1/K 80 ?0 N/A 353 2.83286119*10-3 50 21 -3.044522438 324 3.086419753*10-3 45 27 -3.295836866 316 3.164556962*10-3 40 42 -3.737669618 315 3.174603175*10-3 35 70 -4.248495242 311 3.215434084*10-3 30 113 -4.727387819 304 3.289473684*10-3 Questions: 1. ...read more.

Middle

3. Based on your results, is it advisable to perform the experiment at high temperatures such as 80?? From the above results, the time of the reaction is shorter as the experiment temperature increase. So it is not advisable to perform the experiment at high temperatures as the time of reaction is too short, it is not easy for us to record. 4. Why is it not necessary to know how far the reaction has proceeded at the point where the methyl red is decolourized? In the experiment, the number of mole and the molarity of each chemicals used are the same. ...read more.

Conclusion

Also the rate constant k is proportional to the rate of the reaction when the temperature changes. Therefore, can substitute k. (b) Derive an equation relating ln k and 1/T. ln k = ln A - Ea/RT ln k = ln A - (Ea/R)(1/T) (c) Determine Ea by plotting a suitable graph. (Given R=8.3JK-1 mol-1 ) Slope=[-4.727387819-(-3.044522438)]/(3.289473684*10-3-3.086419753*10-3) =-8287.78 ? lnk = lnA - Ea/RT The slope=-Ea/R ?-8287.78=-Ea/R Ea=8287.78*8.314 =68904.6 J mol-1 =68.9046 kJ mol-1 6. Explain why the reaction rate can be affected by temperature. As the temperature increase, the numbers of vibration increase, the speed of the particles increase, then the frequency of collision increases. As the result, the frequency of effective collision also increases. Therefore the reaction rate will increase vice versa. ...read more.

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