To find out what happens to the efficiency of a motor as I change the mass it lifts.

Authors Avatar

Coursework – Energy

Aim: To find out what happens to the efficiency of a motor as I change the mass it lifts.

METHOD

When devices transfer energy, only part of it is USEFULLY TRANSFERRED to where it is wanted and in the form that it is wanted. The rest is transferred in some non-useful way and therefore it is ‘wasted’. The ‘wasted’ energy and the ‘useful’ energy are both eventually transferred to the surroundings. The greater the proportion of energy supplied to a device, THAT IS USEFULLY TRANSFERRED, the more efficient we say the device is.

        A motor is a device that transfers electrical energy into rotational kinetic energy, which can be used to lift a load. We are going to try and find out how the efficiency of a motor differs as we change the mass that it is required to lift. To do this we will let a small electric motor lift a small load 0.5m off the ground and work out it’s efficiency, increasing the weight of the load it has to lift by 0.1N each time we run it. Below is a diagram showing how the circuit for this experiment will be set up:

 As you can see, the motor has to be connected to the ammeter, voltmeter and the power supply. The ammeter is placed in series and the voltmeter is placed in parallel. The motor should be clamped tightly onto a stand over one metre off the ground. A piece of string capable of reaching to the floor should be attached to the spindle of the motor, whilst the other end should be attached to the mass hook.

When the experiment is run, a stopwatch should begin timing as the power supply is switched on. Whilst the load is being lifted the amps should be read from the ammeter, and the volts from the voltmeter, at the same time. Once the load has been lifted 0.5 metres the timing should be stopped and the data recorded: weight (N), volts (V), amps (A), time (s). The basic raw data from the experiment has now been obtained. This process is repeated twice for each different weight that is lifted, amounting to a total of three runs per change in weight.

        The purpose of the volts, amps and time readings is to calculate the electrical energy supplied to the motor as it runs, or the total energy input, required later for calculating the efficiency. To calculate the total electrical energy supplied to any device we need to use to use the following formula:

ELECTRICAL ENERGY (J) = VOLTS (V) × AMPS (A) × TIME (s)

The volts, amps and time values were multiplied together to calculate the total electrical energy supplied to the motor in our experiment, as you can see in Table #1 in the Tables of Data section in the column headed Electrical Energy.

Prediction

There has to be a weight that a motor is incapable of lifting. So although the motor can do more work by drawing more current, it must become less efficient.

I predict that the line of best fit showing the trend on my results graph will look like:

 

In other words, as the mass of its load increases, the efficiency of the motor will decrease by a uniform rate.

        I predict this because the heavier the weight, the more rotational kinetic energy will be required to turn the motor’s ‘spindle’ to lift the weight. An increase in the amount of rotational kinetic energy being transferred must also result in:

  • An increase in friction affecting the motor’s moving parts, causing energy to be wasted in the forms of heat and sound.
  • An increase in the current drawn by the motor. This causes an increase in the resistance of the wires connecting the motor to the power supply, which in turn causes electrical energy to be wasted in the form of heat, lowering the amount of useful energy output, and therefore lowering the motor’s efficiency.

Calculating Efficiency

In order to find the motor’s efficiency each time we shall have to calculate several values. Firstly we need the raw data obtained from the experiment:

  • Weight Lifted (N): the weight the motor is lifting in Newtons.
  • Height (m): the height in meters that the load is lifted – always 0.5m.
  • Volts (V): the voltage taken from the voltmeter in the circuit.
  • Amps (A): the number of amps read from the ammeter in the circuit.
  • Time (t): the time in seconds that it takes the motor to lift it’s load 0.5m (50cm).

We then need:

  • Average Electrical Energy (J): the average electrical energy supplied to the motor in Joules.
  • G.P.E. (= Movement energy) transferred (J): this is the useful energy output we get from the motor in Joules.

Which allows us to calculate:

  • Efficiency (as a value between 0 and 1): the efficiency of the motor based on all the other values.

On to a graph I can then plot:

  • Weight/Newtons Lifted

Against

  • Efficiency

RESULTS

Tables of Data

Below is the data that I used to calculate the motor’s efficiency, set out in three tables of values, though the calculations used to convert the values are explained later. All of the numbers are given to two decimal places.

Note: The calculations for these values will be explained later.

Table #1: This table displays the three measurements of electrical energy taken each time the motor was run, and the weights it was required to lift.

*     =    counted as an anomalous result – not included when averaging data    

Table #2: This table displays the average electrical energy supplied to the motor, the change in G.P.E. of the motor (the useful output) and the efficiency of the motor worked out from the other values.

Table #3: This table displays the values to be plotted onto my results graph: Newtons lifted (weight of load) against efficiency.

ANALYSING AND CONCLUDING

Below is a diagram of a running motor. An explanation of what is happening is given below.

  1. Electrical energy is supplied to the motor.
  1. Some of this electrical energy is transferred into the desired movement (rotational kinetic) energy in the motor – this is useful energy.
  2. Some of the electrical energy is transferred into non-useful thermal (heat) and sound energy – this is waste energy.
  1. The waste energy is lost to the surroundings.
  2. In this case the movement energy is now transferred into gravitational potential energy when the load is lifted.

Energy has to be transferred from one form to another, e.g. a hairdryer turns electrical energy from a mains supply into movement energy (the fan), heat energy (to heat the air as it passes through) and sound energy (waste energy). You cannot create it or destroy it. Energy efficiency is how much of the energy you put into an appliance or machine is transferred into the useful energy that you are trying to get out. All machines in the real world have an efficiency that is less than 1 (or 100%). In the case of the motor above, part of the electrical energy put in is transferred into the useful movement energy, however, the machine also transfers it’s energy into two other waste forms: it creates a little heat and a little sound, caused by the force of friction on it’s moving parts, as in all machines. The greater the proportion of energy supplied to a device, that is usefully transferred, the more efficient the device.        

Join now!

        To calculate the efficiency of any device we need to use to the following formula:

EFFICIENCY = USEFUL ENERGY TRANSFERRED BY DEVICE

                       TOTAL ENERGY SUPPLIED TO DEVICE

… So in the case of an appliance that coverts 200 joules of electrical energy per second into 150 joules/sec of waste heat energy, 20 joules/sec of useful light energy and 30 joules/sec useful sound energy… EFFICIENCY = 50 ÷ 200 [× 100] = 25%

We are trying to find out how the efficiency of a motor ...

This is a preview of the whole essay