Confirming Hess's Law Experiment

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Hess’ Law Lab

HYPOTHESIS

The heat of combustion for magnesium can be calculated by determining the heat of reaction for the following reactions:

1) Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g)

2) MgO(s) + 2HCl(aq) → MgCl2(aq) + H2O(l)

3) H2(g) + ½ O2(g) → H2O(l)

Once these values have been obtained, one can add or subtract these values in order to achieve the heat of combustion for magnesium.

VARIABLES

Independent:         • Type of chemicals used

        • Amount of chemicals used

Dependant:        • Change in enthalpy

Controlled:        • Elevation

        • Air pressure

        • Room temperature

        • Equipment

        • Humidity

OBSERVATIONS

Qualitative:

Hydrochloric acid solution:

- transparent, water-like liquid

Magnesium metal strip:

- dull silver, grey strip

- extremely ductile

Magnesium oxide:

- fine, white powder

- flour-like appearance

Reaction #1 between hydrochloric acid solution and magnesium metal strip:

- soft fizzing noise coming from the calorimeter

- calorimeter is warm to touch

Reaction #1 upon removing the Styrofoam cup cover:

- clear solution

- magnesium metal strip has fully dissolved in the hydrochloric acid solution

- pungent smell

- bubbles are apparent at the side of the cup

Reaction #2 between hydrochloric acid solution and magnesium oxide:

- calorimeter is slightly warm to touch

- no apparent noise

Reaction #2 upon removing the Styrofoam cup cover:

- clear solution

- magnesium oxide has fully dissolved in the hydrochloric acid solution

- bubbles are apparent at the side of the cup

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Quantitative:

Table 1: Data observed for Reaction #1 between hydrochloric acid solution and magnesium metal strip

Table 2: Data observed for Reaction #2 between hydrochloric acid solution and magnesium oxide

CALCULATIONS

Reaction #1: Mg(s) + HCl(aq) → MgCl2(aq) + H2(g)

ΔT = Tf – Ti

ΔT = (34.5 ± 0.1°C) – (21.3 ± 0.1°C)

= (13.2 ± )°C

= 13.2 ± 0.14 °C

Q = - mcΔT

mMg = 0.291 ± 0.001g

mHCl = (D) (V)

= (1.016g/mL)(100.0 ± 0.5mL)

= 101.6 ± 0.5g

mtotal = (0.291 ± 0.001g) + (101.6 ± 0.5g)

= (101.9 ± )g

= 101.9 ± 0.5g

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