To determine the correct equation of the thermal decomposition of copper carbonate.

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Chemistry coursework –planning

Aim- To determine the correct equation of the thermal decomposition of copper carbonate.

The two possible equations are shown below:

Equation 1:

Equation 2:

I shall first calculate the gas that would be collected by both equations and then talk bout the method used to decompose the copper carbonate and collect the gas.  Then I will explain how you would compare the actual gas collected to your to two theoretical values of gas produced and thus find out the correct equation.

Calculations

Equation 1:

I shall now calculate the expected gas to be given off if equation 1 is correct.

Using 0.1 grams of copper carbonate:

Moles of copper carbonate used = mass / relative molecular mass

Mass = 0.1 grams

R.M.M of copper carbonate = 63.5 + 12 + (16 x 3) = 123.5 grams

Moles = 0.1 / 123.5 = 8.1 x 10-4

If we now compare the moles of copper carbonate to the moles of gas (oxygen + carbon dioxide) given off with find that the molar ratio of the equation is 2:2.5 or 1:1.25.

So to find the gas given off given the moles of copper carbonate we multiply the moles of copper carbonate by 1.25, as 2.5 / 2 = 1.25.

Join now!

moles of gas.= 8.1 x 10-4  x 1.25

moles of gas = 0.00101 moles

I Shall now use the ideal gas equation to calculate the gas produced to actual room temperature and pressure.

The Ideal Gas Law (General gas equation):

PV = nRT


Where

P=pressure

V=volume

n=moles of gas

T=temperature

R = 8.314J K-1 mol-1

For P is shall use standard pressure which is 1 atmosphere = 103kpa

For T I shall use a standard 20oC which is 293K

Moles = 0.00101

Calculating Volume of Gas: V = (nRT) ÷ P

Volume ...

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