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GCSE Chemistry Coursework:Is there a pattern in the structure of alcoholsAnd there energy values?

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David Bennett GCSE Chemistry Coursework: Is there a pattern in the structure of alcohols And there energy values? Hypothesis I don't think that there is a pattern is the structure of alcohols and the energy value. For example why should Propan-1-ol give out more or less energy than propan-2-ol if it is the same only set out slightly different. I predict that propan-1-ol will give the same as propan-2-ol and that butan-1-ol will give the same as butan-2-ol because they are basically the same thing set out differently. Equipment * Card board and tin foil 'Chimney' * Heat proof mat * Tripod * Metal gauze * 100ml beaker (50mls of water) * thermometer * crucible * mineral wool * alcohols (2mls of each) Alcohols Propan-1-ol C3H7OH H - C - C - C - OH Propan-2-ol C3H7OH H - C - C - C - H Butan-1-ol C4H9OH H - C - C - C - C - OH Butan-2-ol C4H9OH H - C - C - C - C - H Diagram Method First of all we set up the equipment as shown in the diagram. ...read more.


The average results are: Propan-1-ol =30+27+38 3 = 31.6�C Propan-2-ol =28+38+29 3 = 31.6�C Butan-1-ol =24+31+33 3 = 29.3�C Butan-2-ol =29+30+31 3 = 30�C As you can see propan-1-ol and propan-2-ol are exactly the same and butan-1-ol and butan-2-ol are also pretty close. Graphs As you can see from the graphs the lines are ending at nearly the same place each time clearly showing that they are giving off more or less the same amount of heat to the water. Analysis Specific Heat Capacity e=mc? Water - 4.2j-1K-1 Copper - 0.38j-1K-1 Glass(thermometer) - 0.67j-1K-1 Mass e=mc? Propan-1-ol - 2mls = 1.37g Propan-2-ol - 2mls = 1.51g Butan-1-ol - 2mls = 1.42g Butan-2-ol - 2mls = 1.66g ?= Temperature change e=mc? Propan-1-ol e=mc? Water e = 50 x 4.2 x 31.6 = 6636j Copper crucible e = 75.29 x 0.38 x 31.6 = 904j Thermometer e = 11.29 x 0.67 x 31.6 = 239j e = 7779j Propan-2-ol e=mc? Water e = 50 x 4.2 x 31.6 = 6636j Copper crucible e = 75.29 x 0.38 x 31.6 = 904j Thermometer e = 11.29 x 0.67 x 31.6 = 239j e= 7779j Butan-1-ol e=mc? ...read more.


The set up of our experiment was okay but it could have been a lot better. The chimney we used was too fiddly, and it prevented us from seeing when the flame had gone out. I think that if we made it out of some kind of transparent material the experiment would have gone a lot better. To make the test fair we used the exact same amount of water and alcohol each time and made sure that everything was set out in the same place each time. In our preliminary work we found that using 100mls of water was too much. The alcohols weren't heating the water up enough to get good results. On the actual day we decided to use 50mls of water and found it to be a lot more accurate. I think that our results were very reliable and sufficient to support the conclusion, we had a range of results all very similar that were averaged, nothing was really wrong with them at all. All though my prediction was wrong I feel that I now learned something new which is a good thing. I could do another experiment to back up my conclusion, I could use different alcohols like butan-1+2-ol and pentan-1+2-ol. Doing this experiment as well would back up my theory a lot. ...read more.

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