Investigating the effect of osmosis on a potato.

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I am investigating the effect of osmosis on a potato. Osmosis is the diffusion of water down a concentration gradient through a semi permeable membrane.

I am investigating the effect of water concentration on the potato chips. This means that I will put potato chips into salt solutions of different concentrations. There are also other factors involved, these are:

- Temperature of water

- Size of chip

- Light

- Mass of potato

- Volume of solution potato is in

- Type of potato

- Time left in solution

- Surface area of potato chip

- Using the same balance to measure chip

If I am going to make this a fair test, then I will have to control these other factors. Doing the tests at one fixed temperature will control the temperature of the water. For the purpose of my experiment I am going to do all the experiments at room temperature.

The size of the potato is very important. This is because if the size of the potato varies, so will the amount of mass it can loose or gain. I am going to try to cut all the pieces of potatoes, to the same size. Because of the ‘chipper´ I will have chips with the same width and height, but the length of the chips will differ. I am going to cut the chips to 3cm in length. essaybank.co.uk

The light intensity cannot really me measured or kept the same, as the chips will be moved from one room to another, for storage. However I will try to keep the chips in the same place when I am storing them.

The mass of the potato is a variable, and this means that it will be measured throughout the experiment. I will measure the mass in grams. The potato chip will be measured before it is put in the solution, and after. This will allow us to see whether osmosis has taken place, and how much osmosis has occurred. wwgd gdw esgdgds aygd gdba ngd kcgd gduk. wwcd cdw escdcds aycd cdba ncd kccd cduk.

The volume of the solution that the potato chips are kept in must be the same. The chip must be totally covered in the solution, and the amount of solution will be kept the same because all the chips are the same size. The amount of solution I cover each chip in will be 25ml. wwea eaw eseaeas ayea eaba nea kcea eauk.

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The type of potatoes I will use is going to be kept the same, because different potatoes may absorb at different rates. For this experiment I am going to use the same potato.

The time the potato chip is left in the solution must be kept the same for each chip. This is because more or less solution may be absorbed depending on time. I am going to keep each potato chip in each solution for nine days.

The surface area of the potato chips will be kept the same by having all the chips the same size. This must ...

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