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Osmosis.I predict that the lower the concentration of the sugar solution, the larger the mass of the potato chip will increase because the cell wall of the potato chip will allow the smaller molecules

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Introduction

Science Coursework: Osmosis Variables Independent variables * The concentration of sucrose (sugar) solution. * The temperature of the solution * The size of the potato chips * The type of potato (pore size) The dependant variable is the change in mass of the potato and will be measured in grams. Prediction I predict that the lower the concentration of the sugar solution, the larger the mass of the potato chip will increase because the cell wall of the potato chip will allow the smaller molecules such as the water molecules to pass through but won't allow bigger molecules to pass through such as the sugar molecules. So if there is a high concentration of sucrose in the solution then their will be less water molecules to diffuse into the potato chip, so more water molecules are needed to dilute the solution, therefore the potato chip will decrease in mass because the water molecules have passed from a higher concentration of water molecules to the lower concentration of water molecules. Therefore a potato chip put into a higher concentration of water than sugar in the solution will increase in mass, but a chip put into a solution which has a higher sugar solution than water solution will decrease in mass. ...read more.

Middle

As we know, sucrose molecules can not pass through a cell wall, but it does affect osmosis in potato cells, because if there is a high concentration of sucrose in a solution then there will be a low concentration of water molecules. So in order for the solution to become dilute the water molecules in the potato cell which have a higher concentration than the solution, move to the less concentrated solution of water molecules. This decreases the mass of the potato chip because it has lost water molecules. But if there is a low concentration of sucrose in the solution then there will be a high concentration of water molecules. So the high concentration of water molecules moves to the lower concentration of water molecules in the potato cell causing the potato chip to increase in mass. For instance in my results I put a potato chip weighing 3 grams into a sucrose solution of 0 molecule per dm� concentration, so it had a high water molecule concentration and a low sucrose concentration. After leaving it over night I took the potato chip out and weighed it, the end mass was 5.4 grams so it had increased in mass considerably. ...read more.

Conclusion

There is enough evidence to make a firm conclusion. How ever if I was to repeat the experiment again I might well increase the time of the results to allow more osmosis to happen and possibly find out the saturation point of the chips. Also the range of concentrations was adequate but I could possibly create more concentrations if I repeated the experiment so that I would have more varied results such as concentrations above 1. The cutting of the potatoes could have affected the experiment as although I was recording my results by mass, it could well have affected the surface area and so the overall rate of osmosis could have increased or decreased. So if I was to repeat the experiment again I could have used a machine to cut the potato as it would ensure that all potatoes would be the same weight and dimensions. For more accurate results I could have also weighed each chip on a more accurate scale not at 0.0grams but to about 0.0000grams. When the potato chips were removed from the beakers and dried I may well have dried some potato chips more thoroughly than others and so some could have had more excess water increasing the mass. ...read more.

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