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# Specific Heat Lab

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Introduction

Title: Specific Heat Lab AIM: The aim of this lab is to understand how things heat up - how the temperature of a material changes when heat is donated to it - HYPOTHESIS: VARIABLES: Specific Heat - Specific heat of a material is the amount of heat per unit mass required to raise the temperature of that material by one degree Celsius. MATERIALS: DATA: Brass Table 1 Initial H2O Temp(c) Final H20 Temp(c) Weight (g) Water (mL) Change in Temp(c) Error � 0.05 0.05 0.005 0 .005 0.10 Trial 1 18.90 20.40 53.45 400.05 1.50 Trial 2 17.80 20.00 53.48 401.00 2.20 Steal Table 1 Initial H2O Temp(c) Final H20 Temp(c) Weight (g) Water (mL) Change in Temp(c) Error � 0.05 0.05 0.005 0 .005 0.10 Trial 1 18.90 20.00 49.45 400.05 1.10 Trial 2 16.90 19.90 49.50 399.80 3.00 Aluminum Table 1 Initial H2O Temp(c) Final H20 Temp(c) Weight (g) Water (mL) Change in Temp(c) Error � 0.05 0.05 0.005 0 .005 0.10 Trial 1 18.90 20.20 17.95 400.05 1.30 Trial 2 19.80 21.10 17.95 404.00 1.30 ANALYSIS: Brass Table 2 Specific Heat H2O Mass of H2O H2O Diff. Temp Metal Mass Metal Temp Change Specific Heat A.V. Error (%) Trial 1 4180 0.40005 1.50 0.05345 79.60 589.55 374 55.14 Trial 2 4180 0.401 2.20 0.05348 80.00 861.91 374 126.82 Trial 1 - Brass To find the specific heat of Brass we have to reorder mh2och2o(Ti-Te)metal=mmetalcmetal(Ti-Te)metal to: cmetal= (mh2o*ch2o*(Ti-Te)h2o)/(mmetal*(Ti-Te)metal) ...read more.

Middle

we need to add the estimated error of Te and Ti and use the formula above for the multiplications. cmetal= (mh2o*(Ti-Te)h2o)/(mmetal*(Ti-Te)metal) - We ignore the specific heat of H2O because no error is present. cmetal= (0 .005* 0.10)/( 0.005*0.10) - Our Error Values 464.97= (.40005*1.10)/(.04945*80.00) - Our Results Uncertainty = (0.005/.40005 + 0.10/1.10 + 0.005/.04945 + 0.10/80.00)464.97 Uncertainty = 95.67677 The result is 464.97� 100. Hence our range is from 364.97to 564.97 Trial 2 - Steal To find the specific heat of Steal we have to reorder mh2och2o(Ti-Te)metal=mmetalcmetal(Ti-Te)metal to: cmetal= (mh2o*ch2o*(Ti-Te)h2o)/(mmetal*(Ti-Te)metal) cmetal= (.3998*4180*3.00)/(.0495*80.10) cmetal= (5013.492)/(3.964) cmetal= 1264.45 To find the percentage error for our specific heat we use the following formula: |Accepted Value - Our Value | / (Accepted Value * 100) |380 - 1264.45| / 380 * 100 884.45/38000 232.75% The error for Steal on our first trial is 232.75% To find the uncertainties in our measurement we reorder the following formula Error Q / q = (Error a/a + Error b/b...) to Error Q = (Error a/a + Error b/b...)*q. Because we used cmetal= (mh2o*ch2o*(Ti-Te)h2o)/(mmetal*(Ti-Te)metal) we need to add the estimated error of Te and Ti and use the formula above for the multiplications. cmetal= (mh2o*(Ti-Te)h2o)/(mmetal*(Ti-Te)metal) - We ignore the specific heat of H2O because no error is present. ...read more.

Conclusion

The initial temperature of the metal caused an error because of the instrument we used to measure the temperature. Instead of measuring the temperature of the metal we measured the temperature of the water; hence the temperature of the metal differed from what we used as an initial temperature. 2. Another error could have occurred when measuring the initial and final temperature of the water. 3. The main source of error is the apparatus used, which unveiled itself to be precise but not accurate. With this I mean that the recorded results where very similar to each other, but not correct. An example, in both the brass trials that where conducted, I calculated an uncertainty of � 100, Hence our results where precise but not correct. 4. Another source of error was that on one of our trials we did not use the same materials, but we changed them, hence this can explain why our second trial had a greater error then our first. To conclude this lab helped me understand how transfer of heat works, how certain materials transfer more heat then other; such as aluminum, which is the main reason why we find it everywhere in our kitchen. In this lab we had a great error percentage which was mostly caused by our apparatus, even thou our results was precise. ?? ?? ?? ?? IB Lab Report Form Full Name: Leonardo Arippol Page: 2 Form created by Gary Allan IB Lab Report Form.doc ...read more.

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